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Rama09 [41]
3 years ago
14

+18x^{2}" alt="12x^{4} +30x^{3} +18x^{2}" align="absmiddle" class="latex-formula">

Factorize
Mathematics
1 answer:
nika2105 [10]3 years ago
6 0

6x squared (x + 1)(2x + 3)

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Drag each equation to show if it could be a correct first step to solving the equation
mote1985 [20]

Answer:

9(8 + 2 = 10) = 90

9 times 10 = 90

x = 8

5 0
4 years ago
Use the quadratic formula to find both solutions to the quadratic equation
faust18 [17]
The two answers are B and D!
3 0
3 years ago
Read 2 more answers
A commercial builder has a downtown lot with 250 frontage feet on Broadway. The lot is 200’ deep. By code, the builder must allo
Morgarella [4.7K]

Subtract 15 from the depth:

200-15 = 185

Subtract 20 from the width ( 10 from both sides)

250-20 = 230

Area to build on: 185 x 230 = 42,550 square feet.

8 0
4 years ago
7k÷3=21. What is the value of k?
viva [34]
7k/3 = 21
x 3       x3
7k = 63
/7      /7
k = 9
(7(9)/3 = 21    =    63/3 = 21    =    21 = 21)
5 0
3 years ago
Read 2 more answers
a standard deck of cards missing the queen of hearts in the 2 of clubs what is the probability of pulling either an ace or a spa
Butoxors [25]
<h3>Answer:  8/25</h3>

=======================================================

Explanation:

In a standard deck, there are 52 cards.

If this deck is missing the queen of hearts and 2 of clubs, then we really have 52-2 = 50 cards in the deck.

There are 4 aces and 13 spades. Those values add to 4+13 = 17, but we need to subtract off 1 to account for the ace of spades counted twice. We have 17-1 = 16 cards that are either an ace, a spade, or both.

Or you can think of it like saying 13 spades + 1 ace of hearts + 1 ace of diamonds + 1 ace of clubs = 16 cards total.

-----------------

The event space has A = 16 cards in it, while the sample space has B = 50 cards.

The probability we're after is A/B = 16/50 = 8/25

5 0
3 years ago
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