Check the picture below, let's use those two points on the line to get its slope.
![\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{3}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{3}-\stackrel{y1}{1}}}{\underset{run} {\underset{x_2}{2}-\underset{x_1}{0}}}\implies \cfrac{2}{2}\implies 1](https://tex.z-dn.net/?f=%5Cbf%20%28%5Cstackrel%7Bx_1%7D%7B0%7D~%2C~%5Cstackrel%7By_1%7D%7B1%7D%29%5Cqquad%20%28%5Cstackrel%7Bx_2%7D%7B2%7D~%2C~%5Cstackrel%7By_2%7D%7B3%7D%29%20~%5Chfill%20%5Cstackrel%7Bslope%7D%7Bm%7D%5Cimplies%20%5Ccfrac%7B%5Cstackrel%7Brise%7D%20%7B%5Cstackrel%7By_2%7D%7B3%7D-%5Cstackrel%7By1%7D%7B1%7D%7D%7D%7B%5Cunderset%7Brun%7D%20%7B%5Cunderset%7Bx_2%7D%7B2%7D-%5Cunderset%7Bx_1%7D%7B0%7D%7D%7D%5Cimplies%20%5Ccfrac%7B2%7D%7B2%7D%5Cimplies%201)
<h3> Answer:</h3><h2>surface area is 227•1</h2><h2>volume is 321•7</h2>
Step-by-step explanation:
diameter is 8•5
radius is d/2
8•5/2
=4•25
surface area = 4πr^2
4×22/7×4•25×4•25
=1589•5/7
=227•1
Volume= 4/3πr^3
4/3×22/7×4•25×4•25×4•25
4/3×22/7×76•76
=321•7
Hope it helps
plz mark as brainliest
Answer:
<u>5/6 ÷ 7/10 = 1 4/21</u>
Step-by-step explanation:
<u>How did we solve the problem above? When we divide two fractions, such as 5/6 ÷ 7/10, we flip the second fraction and then we simply multiply the numerators with each other and the denominator with each other.</u>
<u>We also simplify the answers to fraction problems whenever possible. hope this helps</u>
So the unit rate is basically how many ounces in 1 cup?
So since there are 64 ounces in 8 cups, you can just divide by 8, to find how many sets of 8 there are in 64.
64 = 8
64 / 8 = 8 / 8
8 = 1
So there are 8 ounces in 1 cup, which is your unit rate.
Answer:
Distance between the points = 10 units
Step-by-step explanation:
Given points:
(0,-2) and (-8,-8)
To find the distance between the two points.
Solution:
Applying distance formula to find the distance between the points.
For points
and
the distance is given as:
![d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
Plugging in the given points in the formula.
![d=\sqrt{(-8-0)^2+(-8-(-2))^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28-8-0%29%5E2%2B%28-8-%28-2%29%29%5E2%7D)
![d=\sqrt{(-8)^2+(-8+2))^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28-8%29%5E2%2B%28-8%2B2%29%29%5E2%7D)
![d=\sqrt{(-8)^2+(-6)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28-8%29%5E2%2B%28-6%29%5E2%7D)
![d=\sqrt{64+36}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B64%2B36%7D)
![d=\sqrt{100}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B100%7D)
![d=\pm10](https://tex.z-dn.net/?f=d%3D%5Cpm10)
Since distance is always positive. So
units.