Answer: 3x-1
Step-by-step explanation:
3(x-2)+5 you distribute the 3 to (x-2) then you get 3x-6+5 then you add the -6+5 which is one... so the answer is 3x-1
<span>B(n) = A(1 + i)^n - (P/i)[(1 + i)^n - 1]
where B is the balance after n payments are made, i is the monthly interest rate, P is the monthly payment and A is the initial amount of loan.
We require B(n) = 0...i.e. balance of 0 after n months.
so, 0 = A(1 + i)^n - (P/i)[(1 + i)^n - 1]
Then, with some algebraic juggling we get:
n = -[log(1 - (Ai/P)]/log(1 + i)
Now, payment is at the beginning of the month, so A = $754.43 - $150 => $604.43
Also, i = (13.6/100)/12 => 0.136/12 per month
i.e. n = -[log(1 - (604.43)(0.136/12)/150)]/log(1 + 0.136/12)
so, n = 4.15 months...i.e. 4 payments + remainder
b) Now we have A = $754.43 - $300 = $454.43 so,
n = -[log(1 - (454.43)(0.136/12)/300)]/log(1 + 0.136/12)
so, n = 1.54 months...i.e. 1 payment + remainder
</span>
The lowest points of the graph are at x= -2 and x=4
at those points, the values of the local minimum are y= -3 and y= -5
Answer:
- x² +3x -8x -24
- (x² +3x) +(-8x -24)
- x(x +3) -8(x +3)
- (x +3)(x -8)
Step-by-step explanation:
This is trying to help you understand a method of factoring trinomials.
The first step is to look at the linear term (-5x) and the constant term (-24) and identify the coefficients and their signs: -5 and -24.
The next step is to identify factors of -24 (the constant) that have a sum equal to -5 (the linear term coefficient). We can look at the ways that -24 can be factored:
-24 = 1(-24) = 2(-12) = 3(-8) = 4(-6)
The sums of these factor pairs are 1-24=-23, 2-12=-10, 3-8=-5, 4-6=-2. Of course, the pair we're looking for is +3 and -8.
The next step from here is to rewrite the linear term using these factors. (-5x=3x-8x) This is the first step of the sequence shown in the figure:
x² +3x -8x -24
The next step is to group these terms in pairs:
(x² +3x) +(-8x -24)
And then, to factor each pair using the distributive property:
x(x +3) -8(x +3)
Finally, finish the factoring, again using the distributive property:
(x +3)(x -8)