Answer:
No. of boxes = 10
Oranges per box = 56
Total no. of oranges = 56*10=560
No. of bad oranges = 560/40= 14
(i) Probability of bad orange = 14/560 = 1/40
(ii) no of oranges expected to be bad = 14 ( found above)
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Answer:
(5 x (-20)) * (100 x (0.7))
Answer:
1. x =0; x = -7
2. x = -3; x = 10
3. x = -5; x = -4
Step-by-step explanation:
(1). 6x² + 42x = 0
6x (x + 7) = 0
6x = 0. OR. x + 7 = 0
x = 0/6. x = 0 - 7
x = 0. x = -7
x = 0
x = -7
(2). x² - 7x - 30 = 0
The factors here are (3, -10)
x² - 10x + 3x - 30 = 0
x ( x - 10) + 3 ( x - 10) = 0
(x + 3) ( x - 10) = 0
x + 3 = 0 OR. x - 10 = 0
x = 0-3. x = 0 + 10
x = -3. x = 10
x = -3
x = 10
(3). x² + 9x + 20 = 0
The factors are ( 4, 5)
x² + 4x + 5x + 20 = 0
x ( x + 4) + 5 ( x + 4) = 0
(x + 5) (x + 4) = 0
x + 5 = 0 . OR. x + 4 = 0
x = 0-5. x = 0 - 4
x = -5. x = -4
x = -5
x = -4
Answer:
Step-by-step explanation:
p + n + d + q = 25
Put everything into quarters.
p and q are equally likely to be drawn
q + n + d + q = 25
There are 3 times as many nickels as quarters
n = 3q
q + 3q + d + q = 25
There is 25% more dimes than quarters.
d = 1.25 q
q + 3q + 1.25q + q = 25
6.25 q = 25
q = 25/6,25
=====================
q = 4
p = 4
d = 1.25 * 4 = 5
n = 12
Answer:
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