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alisha [4.7K]
4 years ago
6

I need help with this.

Mathematics
1 answer:
stich3 [128]4 years ago
4 0
The picture is not clear
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The work of a student to solve the equation 4(2x − 4) = 8 + 2x + 8 is shown below:
shusha [124]
In step two. If we look on the left side of the equation in the first step, it reads 4(2x-4). When a number is multiplying an expression in brackets, we have to multiply every term in the brackets by the number in front of the brackets. In this case, it would be 4*2x + 4*(-4), which is 8x - 16. So the correct option would be the second (8x-16=16+2x) (the right side of the eqtn was 8+2x+8 and if we combine like terms we get 16+2x)
4 0
4 years ago
Read 2 more answers
Find h (x) + g (x) h (x) = x2 + 6x and g (x) = -2x - 3 A. x2 - 4x - 3 B. x2 + 8x - 3 C. x2 + 4x - 3 D. x3 + 4x2 - 3​
skelet666 [1.2K]

Answer:

Step-by-step explanation:

x^2 + 6x - 2x - 3

x^2 + 4x - 3

answer is C

4 0
3 years ago
What is the answer to this equation?<br> 1/2 (4i+8)=-2
Flauer [41]

Answer:

If your looking for I the answer is -3

Step-by-step explanation:

Simplify both sides of the equation

1/2(4i+8)=-2       - Distribute

(1/2) (4i) + (1/2) (8) = -2

The subtract 4 from both sides

Then divide both sides by 2

5 0
3 years ago
What is the sum of the solutions of x2 + 9x + 20 = 0?
ZanzabumX [31]

Answer:

Sum of the solutions of x^2+9x+20=0 is -9.

Product of the solutions of 6x^2+7x=3 is -0.50

Step-by-step explanation:

1. x^2+9x+20=0

Given:

The expression whose sum of the solution is required is given as:

x^{2} +9x+20=0

For a quadratic equation of the form ax^2+bx+c=0 the sum of the solutions is given as:

Sum = \frac{-b}{a}

Here, a=1,b=9,c=20

Therefore, the sum of the solutions = -\frac{9}{1}=-9

2. 6x^2+7x=3

Rewriting the above equation in a standard quadratic equation, we get:

6x^2+7x-3=0

For a quadratic equation of the form ax^2+bx+c=0 the product of the solutions is given as:

Product = \frac{c}{a}

Here, a=6,b=7,c=-3

Therefore, the product of the solutions = \frac{-3}{6}=-0.50

6 0
3 years ago
In the 2008 election there were 28 "blue" states and 22 "red" states as fractions, in the lowest terms, of the total number of s
zloy xaker [14]
Red states: 11/25 (simplified)
.44
blue states: 14/25 (simplified)
.56
6 0
3 years ago
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