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KengaRu [80]
3 years ago
8

The pressure of a 1-L nitrogen gas sample at 25 ⁰C is 0.30 atm. The pressure of a 1-L oxygen gas sample at the same temperature

is 0.25 atm. The oxygen gas sample is added to the nitrogen container. Argon gas is added to the mixture until the total pressure of the 1-L container reaches 1.00 atm, and the temperature is adjusted to 25 ⁰C. According to Dalton’s Law of Partial Pressures, the contribution of each gas to the total pressure of the gas mixture is: Nitrogen _____________ Oxygen _____________ Argon _____________
Chemistry
1 answer:
ki77a [65]3 years ago
8 0

Answer:

Nitrogen = 0.3 atm

Oxygen = 0.25 atm

Argon  = 0.45 atm

Explanation:

According to Dalton's law of partial pressure, the total pressure in the container is equal to sum of the partial pressures of the individual gases.

Given;

Total pressure of the gases, P_total = 1 atm

Pressure of nitrogen, P_nitrogen = 0.3 atm

Pressure of oxygen, P_oxygen = 0.25 atm

Pressure of argon, P_argon = ?

P_{total} = P_{nitrogen} + P_{oxygen} + P_{argon}\\\\1 \ atm= 0.3 \ atm + 0.25 \ atm + P_{argon}\\\\1 \ atm= 0.55 \ atm +  P_{argon}\\\\ P_{argon} = 1 \ atm - 0.55 \ atm\\\\ P_{argon} = 0.45 \ atm

Therefore, the contribution of each gas to the total pressure of the gas mixture is;

Nitrogen = 0.3 atm

Oxygen = 0.25 atm

Argon  = 0.45 atm

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A 35.161 mg sample of a chemical known to contain only carbon, hydrogen, sulfur, and oxygen is put into a combustion analysis ap
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The empirical formulae is C6H12S02

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Sulphur = (13.54 mg * 32.066 g/mol / 64.066 g/mol) = 6.777 mg of Sulphur

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Oxygen = (100 - (48.62 + 8.16 + 21.64)) = 21.58 %

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Next is to divide by the smallest value

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Sulphur = 0.675/ 0.675 = 1

Oxygen = 1.348 / 0.675 = 1.997 = 2

So therefore the empirical formulae of the sample is C6H12SO2

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