The sulfuric acid can be constituted into different concentrations using distilled water as a diluent.
<h3>What is dilution of acid?</h3>
Dilution of acid is defined as the decrease in the concentration of an acid using water.
For sulfuric acid to be diluted, it is slowly added to distilled water using the following guidelines:
- Add 150 ml of water to the beaker and add the desired amount of acid. This will give a diluted concentration of the given acid.
Learn more about acid here:
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For the equilibrium that exists in an aqueous solution<span> of nitrous acid (</span>HNO2, a weak acid) ... [H+][NO2. –]. [HNO2<span>]. PAGE: 14.1. 2. Which of the following is a conjugate ... Using the following Ka values, indicate the correct </span>order<span> of base strength. </span>HNO2<span>. Ka = </span>4.0<span> × 10–4 .... Calculate the [H+] in a </span>solution<span>that has a </span>pH<span> of 11.70.
i hope thid works
</span>
Answer:
A) They are all acidic.
Explanation:
All 3 of those have acidic qualities in the drink.
Answer options from an alternative source
- fructose
- lactose
- starch
- glucose
- cellulose
Answer:
- fructose -monosaccharide
- lactose - disaccharide
- starch - polysaccharide
- glucose - monosaccharide
- cellulose - polysaccharide
Explanation:
Monosaccharides are carbohydrates that are the simplest form of a sugar. They cannot be further broken down into smaller carbohydrates, and represent the basic building block for carbohydrates. Monosaccharides can form disaccharides, which are the sugar formed when two monosaccharides join together, or polysaccharides, which are chains of monosaccharides.
<span>Well it depends on percentage by what, but I'll just assume that it's percentage by mass.
For this, we look at the atomic masses of the elements present in the compound.
Cu has an atomic mass of 63.546 amu
Fe has 55.845 amu
and S has 36.065 amu
Since there are 2 molecules of Sulfur for each one of Cu and Fe, we'll multiply the Sulfur atomic weight by 2 to obtain 72.13 amu
So we have not established the mass of the compound in amus
63.546 + 55.845 + 72.13 = 191.521
That is the atomic mass of Chalcopyrite. and Iron's atomic mass is 55.845
So to get the percentage, or fraction of iron, we take 55.845 / 191.521
Which comes out to 29.15% by mass
Mass of the sample is not needed for this calculation, but since the question mentions it I would go ahead and check if the question isn't also asking for the mass of Iron in the sample as well, in which case you just find the 29.15% of 67.7g</span>
