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2 years ago

13

Which graph represents a line with a slope of and a y-intercept equal to that of the line y = x – 2?

2 answers:

uysha [10]2 years ago

4 0

Answer:

d or last graph

Step-by-step explanation:

Rudiy272 years ago

3 0

Answer:

The last graph.

Step-by-step explanation:

The first thing we look for is the y-intercept at -2. The only graphs where the line passes through the y-intercept at this point are the first and the last.

The slope of the line we want is -2/3. This means the line decreases; the first graph increases, not decreases, so it must be the fourth one..

Checking the fourth graph, from the y-intercept, we go down 2 and over 3 to find the next point; this means the slope is -2/3 and this is the correct line.

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Given f(x)= 3x+21. A. F(4)=B. F(X)= 50, X=2. C. F(-5)=D. F(X)= -34, X=

nignag [31]

The given function is

$f(x)=3x+2$

A . f(4) means we have to evaluate the function when x = 4.

$f(4)=3(4)+2=12+2=14$ <h2>Therefore, f(4) = 14.</h2>

B. f(x) = 50 means we have to evaluate the function when y = 50.-

$\begin{gathered} 50=3x+2 \\ 50-2=3x \\ x=\frac{48}{3} \\ x=16 \end{gathered}$ <h2>Therefore, f(16) = 50.</h2>

C. f(-5) means we have to evaluate the function when x = -5.

$f(-5)=3(-5)+2=-15+2=-13$ <h2>Therefore, f(-5) = -13.</h2>

D. f(x) = -34.

$\begin{gathered} -34=3x+2 \\ -34-2=3x \\ x=\frac{-36}{3} \\ x=-12 \end{gathered}$ <h2>Therefore f(-12) = -34.</h2>

4 0

1 year ago

Find the midpoint of AB if a (-1,7) and B (11,-1)

Nady [450]

Answer:

(5, 3)

Step-by-step explanation:

<h3>Given </h3>

Points A(-1,7) and B (11,-1)

<h3>To find</h3>

Midpoint of AB

<h3>Solution</h3>

<u>Using midpoint formula</u>

x = (-1 + 11)/2 = 10/2 = 5
y = (7 -1)/2 = 6/2 = 3

Midpoint is (5, 3)

8 0

2 years ago

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If x3 = 27, what is the value of x?

ipn [44]

Answer:

The value of x is 3

Step-by-step explanation:

Given:

$x^3 = 27$

To Find:

x = ?

Solution:

We Know that

$a = (a^3)^\frac{1}{3}$

$a = (a)^\frac{3}{3}$

We can write 27 as $3 \times 3 \times 3$ = $3^3$

Taking cube root on both sides

$(x^3)^{\frac{1}{3} }= (3^3)^{\frac{1}{3}}$

$x^{\frac{3}{3}} = 3^{\frac{3}{3}}$

$x^1 = 3^1$

x = 3

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3 years ago

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marysya [2.9K]

If I read this right, the answer should be $x^{2y+4}y^{2}+x^{2y+5}y+4x^{2}y^{2}+4xy^{3}$ .

Hope that helped!!

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alukav5142 [94]

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