Answer:
ST=10
Step-by-step explanation:
let x represent the number of apples and y represent the number of oranges.
TOTAL: x + y = 112
y = 112 - x
PEELED: ![\frac{3}{8}x = \frac{1}{2}y](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B8%7Dx%20%3D%20%5Cfrac%7B1%7D%7B2%7Dy)
![(8)\frac{3}{8}x = (8)\frac{1}{2}y](https://tex.z-dn.net/?f=%288%29%5Cfrac%7B3%7D%7B8%7Dx%20%3D%20%288%29%5Cfrac%7B1%7D%7B2%7Dy)
3x = 4y
3x = 4(112 - x)
3x = 448 - 4x
7x = 448
x = 64
y = 112 - x
= 112 - 64
= 48
a) There are 64 apples and 48 oranges
Peeled apples:
= 3(8) = 24
Unpeeled apples: 64 - 24 = 40
Unpeeled - Peeled: 40 - 24 - 16
b) there are 16 more unpeeled apples than peeled apples
Using the hypergeometric distribution, it is found that there is a 0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.
In this problem, the bulbs are chosen without replacement, hence the <em>hypergeometric distribution</em> is used to solve this question.
<h3>What is the hypergeometric distribution formula?</h3>
The formula is:
![P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20h%28x%2CN%2Cn%2Ck%29%20%3D%20%5Cfrac%7BC_%7Bk%2Cx%7DC_%7BN-k%2Cn-x%7D%7D%7BC_%7BN%2Cn%7D%7D)
![C_{n,x} = \frac{n!}{x!(n-x)!}](https://tex.z-dn.net/?f=C_%7Bn%2Cx%7D%20%3D%20%5Cfrac%7Bn%21%7D%7Bx%21%28n-x%29%21%7D)
The parameters are:
- x is the number of successes.
- N is the size of the population.
- n is the size of the sample.
- k is the total number of desired outcomes.
In this problem:
- There are 12 bulbs, hence N = 12.
- 3 are defective, hence k = 3.
The third defective bulb is the fifth bulb if:
- Two of the first 4 bulbs are defective, which is P(X = 2) when n = 4.
- The fifth is defective, with probability of 1/8, as of the eight remaining bulbs, one will be defective.
Hence:
![P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20h%28x%2CN%2Cn%2Ck%29%20%3D%20%5Cfrac%7BC_%7Bk%2Cx%7DC_%7BN-k%2Cn-x%7D%7D%7BC_%7BN%2Cn%7D%7D)
![P(X = 2) = h(2,12,4,3) = \frac{C_{3,2}C_{9,1}}{C_{12,4}} = 0.2182](https://tex.z-dn.net/?f=P%28X%20%3D%202%29%20%3D%20h%282%2C12%2C4%2C3%29%20%3D%20%5Cfrac%7BC_%7B3%2C2%7DC_%7B9%2C1%7D%7D%7BC_%7B12%2C4%7D%7D%20%3D%200.2182)
0.2182 x 1/8 = 0.0273.
0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.
More can be learned about the hypergeometric distribution at brainly.com/question/24826394
Answer:
12!
Step-by-step explanation: