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3 years ago

820 round to the nearest hundred

1 answer:

4 0

Hello! Seeings 20 is less than 50, you then need to round down. If its over 50 then you round up! So if you have 14 its rounded to 10. And if you have 16 round it to 20. So 820 is rounded to 800.

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Answer right and get brainliest and get a thanks ! :-)

nata0808 [166]

The formula used in this problem is $f(t) = f_{1} * r^{t-1}$ , where r is the common ratio. The common ratio is how you get from one term to the next. In this case, the common ratio is ·4, so from one year, or term, to the next the number of frogs is multiplied by four. This makes the answer B. The number of frogs quadruples every year.

5 0

3 years ago

Read 2 more answers

Raj encoded a secret phrase using matrix multiplication. Using A = 1, B = 2, C = 3, and so on, he multiplied the clear text code

Natali5045456 [20]

Answer:

THE CORN IS YUMMY

Step-by-step explanation:

Understanding the question:

Raj encoded a secret phrase using matrix multiplication. For that he first converted each letter in that phrase to integers using the following codes:

A=1,B=2,C=3,D=4,E=5,F=6,G=7,H=8,I=9,J=10,K=11,L=12,M=13,N=14,O=15,P=16,Q=17,R=18,S=19,T=20,U=21,V=22,W=23,X=24,Y=25,Z=26

We suppose that Raj had a matrix X formed by letters of that phrase encoded in integers/numbers. And he multiplied that matrix X with matrix C to get an encoded matrix, let us say 'encoded X'.

Where; C = $\left[\begin{array}{ccc}2&5\\1&2\end{array}\right]$

and encoded X = $\left[\begin{array}{ccc}85&111&135&111&95&101&153\\38&48&55&45&41&44&64\end{array}\right]$

What we need now is X.

Raj got from the phrase to encoded matrix by:

1. Encoding each letter into numbers and forming a matrix X.

2. Multiplying that matrix with another Matrix C to obtain the given encoded matrix.

To find the secret phrase we will reverse the steps as:

1. Multiplying the encoded matrix by 'Inverse of Matrix C' to get matrix X.

2. Converting the elements of X into alphabets.

Inverse of C = (Adjoint of C)/Determinant(C)

Adjoint of $\left[\begin{array}{ccc}2&5\\1&2\end{array}\right]$ = $\left[\begin{array}{ccc}2&-5\\-1&2\end{array}\right]$

Determinant of C = |C| = ad - bc = 2*2 - 5*1 = -1

Inverse of C = $\left[\begin{array}{ccc}2&-5\\-1&2\end{array}\right]$ / (-1)

= $\left[\begin{array}{ccc}-2&5\\1&-2\end{array}\right]$

Multiplying Inverse(C) and encoded X = $\left[\begin{array}{ccc}-2&5\\1&-2\end{array}\right]$ $\left[\begin{array}{ccc}85&111&135&111&95&101&153\\38&48&55&45&41&44&64\end{array}\right]$

= $\left[\begin{array}{ccc}20&8&5&3&15&18&14\\9&19&25&21&13&13&25\end{array}\right]$

Converting these elements back to alphabets, we get:

= $\left[\begin{array}{ccc}T&H&E&C&O&R&N\\I&S&Y&U&M&M&Y\end{array}\right]$

Hence, it is obvious that the secret phrase is "THECORNISYUMMY"

The location of spaces are between every word ( THE CORN IS YUMMY).

4 0

3 years ago

Read 2 more answers

740,000=________ten thousands

sweet-ann [11.9K]

= 40 ten thousands.

3 0

3 years ago

The width of a poster is 8cm less than the length. The perimeter is more than 184

mart [117]

Let the length be x
width = x - 8
Perimeter = Length + Length + Width + Width

x + x + x - 8 + x - 8 > 184
4x - 16 > 184
4x > 184 + 16
4x > 200
x > 50

Therefore:
Length > 50
Width > 50 - 8
Width > 42

Ans: Length > 50, Width > 42

5 0

3 years ago

Solve the following inequality in two ways and make a claim as to which

NikAS [45]

Answer:

The solution of the given inequality n < 5

Step-by-step explanation:

Explanation:-

Given inequality

$\frac{1}{4} (8 n -12 ) < n +2$

Step(i):-

Cross multiplication '4' we get

8 n - 12 < 4 ( n +2)

8 n - 12 < 4 n + 4×2

8 n - 12 < 4 n +8

Subtracting '4 n ' on both sides, we get

8 n - 4 n - 12 < 4 n - 4 n +8

4 n - 12 < 8

Step(ii):-

Adding ' 12 ' on both sides , we get

4 n -12 + 12 < 8 + 12

4 n < 20

Dividing "4' on both sides , we get

n < 5

The solution is n < 5

Conclusion:-

The solution of the given inequality n < 5

5 0

3 years ago