Question

Write the equation of the circle with radius 2 and center (2,-3)

Answer 1

Answer:

$(x-2)^{2} + (y+3)^{2} = 4$

Step-by-step explanation:

Formula

$Centre (a,b) \\Radius r(x-a)^{2} + (y-b)^{2} = r^{2}\\\\Centre (2, -3) \\Radius 2(x-(2))^{2} + (y-(-3))^{2} = 2^{2}\\(x-2)^{2} + (y+3)^{2} = 4$