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Mars2501 [29]
4 years ago
13

Write equations for the constraints and other given information in this problem, the fact that the length of the string does not

change imposes a constraint on relative accelerations of the two blocks. find a relationship between the x component of the acceleration of block 2, a2x, and the acceleration of block 1. pay careful attention to signs. express a2x in terms of a1x and/or a1y, the components of the acceleration vector of block 1.
Mathematics
1 answer:
VikaD [51]4 years ago
7 0
Since there is no picture this is quite hard to answer but there are a<span> few possible scenarios. </span>

<span>Up = y </span>
<span>Right = x </span>

<span>If it has them arranged where block 1 is to the right of block 2 and they're moving horizontally, then we can say that: </span><span>(a_1x) = (a_2x) </span>

<span>If block 1 is projected over a cliff falling down, and block 2 is on the cliff, being pulled by block 1, then we can say that: </span><span>-(a_1y) = (a_2x) </span>

<span>Any time one is dragging the other, using the tension of the string, then the constraint is that the magnitude of a1 would be the same as the magnitude of a2.</span>
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What are the answers for 1-4 this is geometry.
elena-s [515]

Answer/Step-by-step explanation:

1. x*21 = 24*14 (intersecting chords theorem)

21x = 336

x = 336/21

x = 16

2. 27*x = 45² (secant-tangent rule)

27x = 2,025

x = 2,025/27

x = 75

3. (x + 5)*5 = (4 + 6)*6 (Intersecting secants theorem)

5x + 25 = (10)*6

5x + 25 = 60

5x = 60 - 25

5x = 35

x = 35/5

x = 7

4. (4x + 2)*8 = (5x + 1)*7

32x + 16 = 35x + 7

Collect like terms

32x - 35x = -16 + 7

-3x = -9

x = -9/-3

x = 3

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How many whale sharks would a researcher need to measure so that 90% confidence level would have a margin of error of 0.25
Vika [28.1K]

About 1407 sharks would be needed to have a margin of error of 0.25

<h3>What is margin of error?</h3>

Margin of error is used to determine by what value there is deviation from the real value. Margin of error (E) is given by:

E=Z_\frac{\alpha}{2} *\frac{standard\ deviation}{\sqrt{sample\ size} }

The 90% confidence level have a z score of 1.645. Hence for E = 0.25, standard deviation = 5.7 feet, hence:

0.25=1.645*\frac{5.7}{\sqrt{sample\ size}}\\ \\sample\ size=1407

About 1407 sharks would be needed to have a margin of error of 0.25

Find out more on margin of error at: brainly.com/question/10218601

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2 years ago
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