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Tpy6a [65]
2 years ago
14

How many whale sharks would a researcher need to measure so that 90% confidence level would have a margin of error of 0.25

Mathematics
1 answer:
Vika [28.1K]2 years ago
8 0

About 1407 sharks would be needed to have a margin of error of 0.25

<h3>What is margin of error?</h3>

Margin of error is used to determine by what value there is deviation from the real value. Margin of error (E) is given by:

E=Z_\frac{\alpha}{2} *\frac{standard\ deviation}{\sqrt{sample\ size} }

The 90% confidence level have a z score of 1.645. Hence for E = 0.25, standard deviation = 5.7 feet, hence:

0.25=1.645*\frac{5.7}{\sqrt{sample\ size}}\\ \\sample\ size=1407

About 1407 sharks would be needed to have a margin of error of 0.25

Find out more on margin of error at: brainly.com/question/10218601

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Patrick spent a total of $29.82 for 14 paintbrushes, $31.84 for 16 drywall anchor screws, $27.15 for 12 light bulbs, and $36.54
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Answer: Light bulbs.

Step-by-step explanation:

Paint Brushes: 29.82 ÷ 14 = $2.13 per brush.

Drywall Screws : 31.84 ÷ 16 = $1.99 per anchor screw.

Light Bulbs: 27.15 ÷ 12 = $2.26 per light bulb.

Sandpaper: 36.54 ÷ 18 = $2.06 per piece of sandpaper.

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3 years ago
A fish tank has the shape of a rectangular prism. It has a length of 2 1/4 meters, width of 7/8 meters, and a height of 1 1/2 me
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volume = L x W X H

2 1/4 x 7/8 x 1 1/2 = 2 61/64 cubic meters

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3 years ago
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What is 20/10 as a whole number
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Your bank account is sitting on $14,000. You started with a principal balance of $12,500. If the interest rate was 4.5% compound
Simora [160]

Answer:

t=2.5\ years  

Step-by-step explanation:

we know that

The formula to calculate continuously compounded interest is equal to

A=P(e)^{rt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest in decimal  

t is Number of Time Periods  

e is the mathematical constant number

we have  

t=?\ years\\ P=\$12,500\\P=\$14,000\\ r=4.5\%=4.5/100=0.045  

substitute in the formula above   and solve for t

14,000=12,500(e)^{0.045t}  

Simplify

14,000/12,500=(e)^{0.045t}  

1.12=(e)^{0.045t}  

Apply ln both sides

ln(1.12)=ln[(e)^{0.045t}]  

ln(1.12)=(0.045t)ln(e)  

Remember that

ln(e)=1  

so

ln(1.12)=(0.045t)  

t=ln(1.12)/(0.045)  

t=2.5\ years  

3 0
3 years ago
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