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Stolb23 [73]
3 years ago
15

The graph shows that f(x) = 3x is translated horizontally and vertically to create the function g(x) = 3x – h + k. What is the v

alue of h?
Mathematics
2 answers:
zepelin [54]3 years ago
8 0
2 on edgnuity
h=2 .
Anastasy [175]3 years ago
8 0
2=k and 2=h on the test

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konstantin123 [22]
You need to turn 1/2 to .5 and 3/4 to .75 then you use this equation. 
75% * 950,000 (profit)    
+ 25% * -285,000 (loss) 
<span>= then you subtract the numbers from the separate </span>
<span>= answer --> expected profit from the second mall</span>
4 0
3 years ago
4. The first two numbers in a sequence are 3, 9.
likoan [24]

Answer:

234567

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
The diameter of a particle of contamination (in micrometers) is modeled with the probability density function f(x)= 2/x^3 for x
natulia [17]

Answer:

a) 0.96

b) 0.016

c) 0.018

d) 0.982

e) x = 2

Step-by-step explanation:

We are given with the Probability density function f(x)= 2/x^3 where x > 1.

<em>Firstly we will calculate the general probability that of P(a < X < b) </em>

       P(a < X < b) =  \int_{a}^{b} \frac{2}{x^{3}} dx = 2\int_{a}^{b} x^{-3} dx

                            = 2[ \frac{x^{-3+1} }{-3+1}]^{b}_a   dx    { Because \int_{a}^{b} x^{n} dx = [ \frac{x^{n+1} }{n+1}]^{b}_a }

                            = 2[ \frac{x^{-2} }{-2}]^{b}_a = \frac{2}{-2} [ x^{-2} ]^{b}_a

                            = -1 [ b^{-2} - a^{-2}  ] = \frac{1}{a^{2} } - \frac{1}{b^{2} }

a) Now P(X < 5) = P(1 < X < 5)  {because x > 1 }

     Comparing with general probability we get,

     P(1 < X < 5) = \frac{1}{1^{2} } - \frac{1}{5^{2} } = 1 - \frac{1}{25} = 0.96 .

b) P(X > 8) = P(8 < X < ∞) = 1/8^{2} - 1/∞ = 1/64 - 0 = 0.016

c) P(6 < X < 10) = \frac{1}{6^{2} } - \frac{1}{10^{2} } = \frac{1}{36} - \frac{1}{100 } = 0.018 .

d) P(x < 6 or X > 10) = P(1 < X < 6) + P(10 < X < ∞)

                                = (\frac{1}{1^{2} } - \frac{1}{6^{2} }) + (1/10^{2} - 1/∞) = 1 - 1/36 + 1/100 + 0 = 0.982

e) We have to find x such that P(X < x) = 0.75 ;

               ⇒  P(1 < X < x) = 0.75

               ⇒  \frac{1}{1^{2} } - \frac{1}{x^{2} } = 0.75

               ⇒  \frac{1} {x^{2} } = 1 - 0.75 = 0.25

               ⇒  x^{2} = \frac{1}{0.25}   ⇒ x^{2} = 4 ⇒ x = 2  

Therefore, value of x such that P(X < x) = 0.75 is 2.

8 0
3 years ago
Plz help MATH HW<br>explain/answer
Misha Larkins [42]

No because the sum could also be irrational number which for example it could be square root of 9 or 49

       Hope this helps answer your question

6 0
3 years ago
Rearrange the equation so u is the independent variable,<br> 4u + 8w = -3u + 2w<br><br> W=
Katyanochek1 [597]

Answer:

w=-1.16u

Step-by-step explanation:

first you want to put the W's on one side and the U's on the other. we can do this by subtracting 4u from the left side and the right side making the equations 8w=-7u+2w.

next we want to subtract 2w from both sides making the equation 6w=-7u then we divide by 6 to get w=-1.16u

3 0
2 years ago
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