All categories

2 years ago

What is the biconditional statement of the following conditional statement?

1 answer:

4 0

Based on the given conditional statement, the biconditional statement would be The sum of two angles is 180° if and only if the angles are supplementary.

<h3>What is the biconditional statement?</h3>

A biconditional statement takes a conditional statement and restates it while also stating its converse.

To do so, it will often use the words, "if and only if" to emphasize the condition required.

The biconditional statement here is therefore:
" The sum of two angles is 180° if and only if the angles are supplementary."

Find out more on biconditional statements at brainly.com/question/24528571

#SPJ1

You might be interested in

Felicia is building a rectangular garden. The garden will have a perimeter of 20 meters. Give three pairs of possible side lengt

Lynna [10]

8 and 2: 8+8+2+2
7 and 3: 7+7+3+3
6 and 4: 6+6+4+4
=20

5 0

3 years ago

Which number can each term of the equation be multiplied by to eliminate the fractions before solving?

Lerok [7]

To eliminate the fraction, we multiply by 4

<h3>How to eliminate the fractions?</h3>

The equation is given as:

-3/4m-1/2=2+1/4m

Rewrite properly as:

$-\frac{3}{4}m - \frac 12 = 2 + \frac 14m$

The denominators of the above fractions are 2 and 4

The LCM of 2 and 4 is 4

So, we multiply through by 4.

This gives

-3m - 2 = 8 + m

Hence, to eliminate the fraction, we multiply by 4

Read more about fractions at:

brainly.com/question/10354322

#SPJ1

7 0

2 years ago

A particle moves along the x-axis so that at any time t>0, its acceleration is given by a(t) = ln(3^t + 1). If the velocity o

Aleksandr [31]

Answer: The answer is 11.630

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

A random sample of n = 45 observations from a quantitative population produced a mean x = 2.5 and a standard deviation s = 0.26.

oee [108]

Answer:

P-value (t=2.58) = 0.0066.

Note: as we are using the sample standard deviation, a t-statistic is appropiate instead os a z-statistic.

As the P-value (0.0066) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the population mean μ exceeds 2.4.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the population mean μ exceeds 2.4.

Then, the null and alternative hypothesis are:

$H_0: \mu=2.4\\\\H_a:\mu> 2.4$

The significance level is 0.05.

The sample has a size n=45.

The sample mean is M=2.5.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=0.26.

The estimated standard error of the mean is computed using the formula:

$s_M=\dfrac{s}{\sqrt{n}}=\dfrac{0.26}{\sqrt{45}}=0.0388$

Then, we can calculate the t-statistic as:

$t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{2.5-2.4}{0.0388}=\dfrac{0.1}{0.0388}=2.58$

The degrees of freedom for this sample size are:

$df=n-1=45-1=44$

This test is a right-tailed test, with 44 degrees of freedom and t=2.58, so the P-value for this test is calculated as (using a t-table):

$P-value=P(t>2.5801)=0.0066$

As the P-value (0.0066) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the population mean μ exceeds 2.4.

7 0

3 years ago

A company buys a sweater for $14 and marks it up 90%. It later discounts the sweater 25%.

Goryan [66]

Answer:

$12.6 after marking it up by 90%

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers