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Radda [10]
3 years ago
11

If angle abd=82, what is angle abe

Mathematics
1 answer:
Alik [6]3 years ago
5 0
Angle abe equals 41 as the bisector divides the angle in half.
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PLZZZZ HELP FAST!!!!
Volgvan

Divide by 6... For part E, you should know every ingredient for 1 serving by then, so mu multiply by 10

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3 years ago
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What is the simplified expression for -3(2x-y)+2y + 2(x+y)?
slamgirl [31]

Answer:

- 3(2x - y) + 2y + 2(x + y) \\  - 6x + 3y + 2y + 2x + 2y \\ =   - 4x + 7y

I hope I helped you^_^

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Suppose ABCD is a rhombus with AB = 12 inches. The midpoints of its sides are joined to form a quadrilateral. What type of quadr
MrRissso [65]

Answer:

A rectangle

Step-by-step explanation:

The given parameters are;

The quadrilateral ABCD is a rhombus;

The length of the sides of the rhombus = 12 inches

The lengths of the sides of a rhombus are equal

The opposite interior angles of the rhombus are equal

The length of each midpoint from the vertex = 12 in./2  = 6 in.

Therefore, we have;

The line joining the midpoints form a quadrilateral with the length of the opposite sides equal

The sum of the interior angles of the rhombus = 180°

From the diagram created with Microsoft Visio, we have;

4·a + 4·b + 360 = 4 × 180 = 360 + 360

4·a + 4·b = 360

a + b = 90°

We have;

The interior angles of the quadrilateral formed = x

a + b + x = 180° Sum of angles on a straight line

∴ x = 180° - (a + b) = 180° - 90° = 90°

x = 90°

Therefore, the interior angles of the quadrilateral formed = 90°

The quadrilateral formed having equal opposite sides, and all interior angle of 90° each is a rectangle

6 0
3 years ago
Algebra 2 Please Help
hammer [34]
No sé lo que quieres decir
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3 years ago
Only one of the comparisons below is correct. Which is correct? What benchmark was used in your answer?
tiny-mole [99]

Answer:

2/3<9/10; I used 3/4 as a benchmark.

Step-by-step explanation:

2/3<1/2; I used 1/2 as a benchmark.

2/3 = 0.(20/3) = 0.667

1/2 = 0.(10/2) = 0.5

So this is wrong, as 0.667 > 0.5.

1/2=3/5; I used 1/4 as a benchmark.

1/2 = 0.(10/2) = 0.5

3/5 = 0.(30/5) = 0.6

0.5 != 0.6, so this is wrong.

2/3<9/10; I used 3/4 as a benchmark.

2/3 = 0.(20/3) = 0.667

9/10 = 0.(90/10) = 0.9

So this is correct, as 0.667 < 0.9

3/4<2/3; I used 1/2 as a benchmark.

3/4 = 0.(30/4) = 0.75

2/3 = 0.(20/3) = 0.667

0.75 > 0.667, so this is wrong.

5 0
3 years ago
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