Question

Given f(x)= 17- X? what is the average rate of change in f(x) over the interval [1, 5]?

Answer 1

Answer:

answer is -6

Step-by-step explanation:

Here,

Let [1,5] be[a,b]

f(x)=17-x²

f(a)=17-a²=17-1²=17-1 = 16

f(b) = 17-b² = 17-5² = 17-25 = -8

now, using formula,

{f(b)-f(a)}/(b-a)

(-8-16)/(5-1)

-24/4

=-6

Answer 2

Answer:

first option

Step-by-step explanation:

The average rate of change of f(x) in the closed interval [ a, b ] is

$\frac{f(b)-f(a)}{b-a}$

Here [ a, b ] = [ 1, 5 ]

f(b) = f(5) = 17 - 5² = 17 - 25 = - 8

f(a) = f(1) = 17 - 1² = 17 - 1 = 16 , then

average rate of change = $\frac{-8-16}{5-1}$ = $\frac{-24}{4}$ = - 6