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ki77a [65]
3 years ago
11

A talent competition on television had five elimination rounds. After each elimination, only one-third of the contestants were s

ent to the next round. The table below shows the number of contestants in each round of the competition:
x 1 2 3 4 5
f(x) 243 81 27 9 3

Compute the average rate of change of f(x) from x = 1 to x = 4 and describe what it represents.

A. −78 contestants per round, and it represents the number of contestants who will reach the final round
B. −234 contestants per round, and it represents the number of contestants who will reach the final round
C. −234 contestants per round, and it represents the average rate at which the number of contestants changed from the first round to the fourth round
D. −78 contestants per round, and it represents the average rate at which the number of contestants changed from the first round to the fourth round
Mathematics
2 answers:
Vsevolod [243]3 years ago
8 0

Given the number of contestant in each round:

X      1    2    3    4    5

F(x) 243 81 27  9    3

Rate of change can be calculated using y2-y1/x2-x1 formula. From rounds 1 to 4 the rate of change are

-162, -54, -18. And the average of it is -78 and it represents the average rate at which the number of contestants changed from the first round to the fourth round.

navik [9.2K]3 years ago
5 0

Answer:

X      1    2    3    4    5

F(x) 243 81 27  9    3

Step-by-step explanation:

Rate of change can be calculated using y2-y1/x2-x1 formula. From rounds 1 to 4 the rate of change are

-162, -54, -18. And the average of it is -78 and it represents the average rate at which the number of contestants changed from the first round to the fourth round.

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If triangle ABC is dilated by a scale factor of 2 with a dilation center of A, what will be the coordinates of point b’?
mojhsa [17]

Answer:


In the given figure the sides of triangle measures as follows:


AB= 4 units,


BC= 6 units,


Since triangle ABC is right angled triangle, to find AC we will have to use Pythagorean theorem,


AB² + BC² = AC²


Plugging the values of AB and BC to find AC,


4² + 6² = AC²


16+36=AC²


AC = 7.48


Now if the triangle is dilated by a scale factor of 2, each side will be multiplied by 2 to get the new triangle A'B'C'


side A'B' = 2* AB = 2*4= 8 units


side B'C' = 2* BC = 2*6 =12 units


side A'C' = 2*AC = 2*7.48 = 14.96 units


Perimeter of triangle = sum of three sides


Perimeter of triangle A'B'C' = A'B' + B'C' + A'C'= 8+12 + 14.96 = 34.96 units.


Perimeter of triangle ABC = AB+BC + AC = 4+6+7.48 = 17.48 units.


Perimeter of triangle A'B'C' = 2* Perimeter of triangle ABC


The perimeter of new triangle A'B'C' is 34.96 units which is twice that of triangle ABC.


Answer : A) The perimeter of A'B'C' is 2 times the perimeter of ABC.



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4 years ago
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3 years ago
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