The ratio of OC to OA is OC/ 10√2 - OC
<u>Explanation:</u>
Given -
AD = 4 cm
M is the midpoint of CD
Ratio of OC to OA = ?
In a square, all the interior angles are 90°
Therefore,
ΔADC, ΔABC and ΔBCM are right angled triangle
AC is the diagonal which divides ∠DAB and ∠DCB equally
If AD = 4 cm, then AB, BC and DC are also 4cm
In ΔADC,
(AC)² = (AD)² + (DC)²
(AC)² = (10)² + (10)²
AC = 10√2 cm
AC = OA + OC
OA = AC - OC
OC/OA = OC / AC - OC
OC / OA = OC / 10√2 - OC
Therefore, the ratio of OC to OA is OC/ 10√2 - OC
% change= (new # - original #) ÷ original # x 100
original #= 98
new #= 62
% change= (62-98)/98 x 100
= -36/98 x 100
= -0.36734 x 100
= -36.73%
Rounded to nearest 10th of %= -36.7%
CHECK:
= 98 - (98 * 36.73%)
= 98 - (98 * 0.3673)
= 98 - 36
= 62 new #
ANSWER:
Her percent error was 36.7% (rounded to the nearest tenth of a percent). The negative indicates a decrease.
Hope this helps! :)
Hello there,
When you reflect a point over the x-axis the x-coordinate stays the same while the y-coordinate is its opposite.
In the given point (4,1) when it is reflected over the x-axis you would get (4, -1).
Hope I helped,
Amna
Answer:
Step-by-step explanation:
Hope this helps you
