The rectangle on the right is 81 and the rectangle on the left is 24. I don't really know about the second one sorry, but I hope this helped.
Answer: provided in the explanation segment
Step-by-step explanation:
(a). from the question, we can see that since that б is known, we can use standard normal, z.
we are asked to find an 80% confidence interval for the average weights of Allen's hummingbirds in the study region. What is the margin of error?
⇒ 80% confidence interval for the average weight of Allen's hummingbirds is given thus;
x ± z * б / √m
which is
3.15 ± 1.28 * 0.32/√10
= 3.15 ± 0.1295 = 3.0205 or 3.2795
(b). normal distribution of weight (c) б is known
(c). option (a) and (e) are correct
(d). from the question, let sample size be given as S
this gives';
1.28 * 0.32/√S = 0.15
√S = (1.28 * 0.32) / 0.15 = 2.73
S = 7.4529
cheers i hope this helps
Answer:
score = 63
Step-by-step explanation:
1. To write the proportion take the score of the test over the number of points and set it equal to the percent over 100
score 90
----------- = -----------
70 100
Using cross products
100 * score = 90*70
100 score = 6300
Divide by 100
100/100 * score = 6300/100
score = 63
Answer:
UV
Step-by-step explanation:
Answer:
35º
Step-by-step explanation:
90-55 = 35º
