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evablogger [386]
3 years ago
9

5 questions plz answer all of them if you do you will get points, thanks, Brainliest answer,

Mathematics
1 answer:
babunello [35]3 years ago
5 0
1. 1/6

2. 1/8

3. 80%

4. 1/5

5. 2/8 or 25%
You might be interested in
Describe two ways to write equivalent algebraic expressions
Zolol [24]

Answer:

See below.

Step-by-step explanation:

An example would be:

3x^2 + 6

and

3(x^2 + 2) .

The second way is found by dividing the first one by 3).

5 0
3 years ago
How do you find endpoints of a line segment with a given endpoint and midpoint?
seraphim [82]

In order to find the second endpoint or a line segment given the first and the midpoint, you need to realize that the midpoint is an average of the two endpoints. Given that fact, we can derive this formula looking at x values of points A and B with midpoint M. Remember this is only looking at the x values.

(A + B)/2 = M

So if we are looking for A, we can solve for A and use this modified formula.

(A + B)/2 = M

A + B = 2M

A = 2M - B

Now we can do this with the y values of these points as well. We then have the coordinates of both parts of A.

6 0
3 years ago
I NEED HELP PLEASE HELP ME
Aloiza [94]
Answer:
294.14cm^2

Explanation:

First find the area of the whole piece of paper:
32*14=448

Then find the area of the two semicircles, semicircle + semicircle = 1 circle:

Area of a circle= (radius squared)(pi):
(7^2)(3.14) = 153.86

Subtract the area of the two semicircles from the whole paper area:
448-153.86 = 294.14


I hope this isn’t too confusing :)


5 0
3 years ago
Given the equation 5x − 4 = –2(3x + 2), solve for the variable. Explain each step and justify your process.
blagie [28]
A.
5x-4=-2(3x+2) \ \ \ \ \ \ \ \ \ |\hbox{expand the bracket} \\
5x-4=-2 \times 3x-2 \times 2 \\
5x-4=-6x-4 \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{add 6x to both sides} \\
11x-4=-4 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{add 4 to both sides} \\
11x=0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{divide both sides by 11} \\
x=0

B.
3(2x-4)=5x-1 \\
6x-12=5x-1 \\
\boxed{11x-12=-1} \Leftarrow \hbox{the first mistake} \\
11x=11 \\
\boxed{x=11} \Leftarrow \hbox{the second mistake}

Megan's solution isn't correct.
The first mistake: she subtracted 5x from the right-hand side of the equation, but added 5x to the left-hand side.
The second mistake: she divided the right-hand side of the equation by 11, but didn't divide the left-hand side.

The correct solution:
3(2x-4)=5x-1 \ \ \ \ \ \ \ \ \ \ \ |\hbox{expand the bracket} \\
3 \times 2x+3 \times (-4)=5x-1 \\ 6x-12=5x-1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{subtract 5x from both sides} \\
x-12=-1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  |\hbox{add 12 to both sides} \\
x=11
3 0
3 years ago
^^ question above! Thanks!
Aleksandr [31]
You can cross multiply and the answer would be 100/9
9/10=10/k
100=9k
k=100/9
7 0
3 years ago
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