Multiply 5730 years by 2 since two half-lives have gone by for carbon.
<u>Explanation</u>:
The half-life of a radioactive isotope depicts the measure of time that it takes half of the isotope in an example decay. On account of radiocarbon dating, the half-existence of carbon 14 is 5,730 years
The half-life of carbon-14 is 5730 years.
In this manner, after
1 half-life there is 50 % = 1/2 of the first amount left.
2 half-lives there is 25 % = 1/4 of the first amount left.
25% is two half-lives.
Every 50% of life requires 5730 years.
So two half-lives require 2 × 5730
The correct answer is A. This is because undeveloped meaning they don't have access to any of the other offered answers
<span>The troposphere is the lowest portion of Earth's atmosphere. It contains approximately 75% of the atmosphere's mass and 99% of its water vapour and aerosols. The average depth of the troposphere is approximately 17 km in the middle latitudes. It is deeper in the tropics, up to 20 km, and shallower near the polar regions, approximately 7 km in winter. The lowest part of the troposphere, where friction with the Earth's surface influences air flow, is the planetary boundary layer. This layer is typically a few hundred meters to 2 km deep depending on the landform and time of day. The border between the troposphere and stratosphere, called the tropopause, is a temperature inversion.</span>
