Answer:

Step-by-step explanation:
Here is the full question
A standard piece of paper is 0.05 mm thick. Let's imagine taking a piece of paper and folding the paper in half multiple times. We'll assume we can make "perfect folds," where each fold makes the folded paper exactly twice as thick as before - and we can make as many folds as we want.
Write a function g that determines the thickness of the folded paper (in mm) in terms of the number folds made, n. (Notice that g(0) 0.05,)

The function g has an inverse. The function g⁻¹ determines the number of folds needed to give the folded paper a thickness of t mm. Write a function formula for g⁻¹).
<u>SOLUTION:</u>
If we represent g(n) with t;
Then

Taking logarithm of both sides; we have :

If you examine the numbers in the question above very well, you will discover that thy have a distinctive pattern. The pattern is this, you add 3 to the first number and then you multiply the next by 2. Lets go over the numbers now:
6 + 3 = 9
9 * 2 = 18
18 + 3 = 21
21 * 2 = 42
42 + 3 = 45
45 * 2 = 90
90 + 3 = 93
93 * 2 = 186, etc.
Thus, the next number after 45 is 90.
H=w=4w^3
l=5w^2-3w-4
A=w•l
A=4w^3(5w^2-3w-4)
A=20w^5-12w^4-16w^3
Good luck
As you can see in the denominator, the values keep on multiplying by 2, meaning that the number must multiply by 0.5 or 1/2 to get the next one.
So the rule is *1/2.