Subtract a from both sides of the equation.
b=−a+14
9! or 9×8×7×6×5×4×3×2×1 which is 362,880
A) zeroes
P(n) = -250 n^2 + 2500n - 5250
Extract common factor:
P(n)= -250 (n^2 - 10n + 21)
Factor (find two numbers that sum -10 and its product is 21)
P(n) = -250(n - 3)(n - 7)
Zeroes ==> n - 3 = 0 or n -7 = 0
Then n = 3 and n = 7 are the zeros.
They rerpesent that if the promoter sells tickets at 3 or 7 dollars the profit is zero.
B) Maximum profit
Completion of squares
n^2 - 10n + 21 = n^2 - 10n + 25 - 4 = (n^2 - 10n+ 25) - 4 = (n - 5)^2 - 4
P(n) = - 250[(n-5)^2 -4] = -250(n-5)^2 + 1000
Maximum ==> - 250 (n - 5)^2 = 0 ==> n = 5 and P(5) = 1000
Maximum profit =1000 at n = 5
C) Axis of symmetry
Vertex = (h,k) when the equation is in the form A(n-h)^2 + k
Comparing A(n-h)^2 + k with - 250(n - 5)^2 + 1000
Vertex = (5, 1000) and the symmetry axis is n = 5.
Answer:
1) 6 balls
Step-by-step explanation:
x = number of balls Elsa can shoot
x + 6 = number of balls Anna can shoot
18 = number of balls together they can shoot
x + (x + 6) = 18
x + x + 6 = 18
2x + 6 = 18
2x = 18 - 6
2x = 12
x = 6
2)2) 20x (3÷ 4)=90 120-90=30 thus left seat has 30 seating capacity.
3)Let x & y be packets of [a] type & [b] type detergent sold
Then 9x +7y =180
Let us say x=7
Then 9*7+7y =180
7y =180–63 = 117
y =117/7=19.2 this will not do as it contains decimal not whole number
Say x=6
Then 9*6 +7y =180
7y=180–54 =126
y =126/7 =18 this is acceptable as it is whole number
Answer: 6 packets of (a) and 18 packets of type (b) were sold to get 180Php
4) 5,6,7 female piglets
5)1kg. of rice is Php. 90.00 . Mang Tommy pays Php.360.00 for 4kg. of rice.
4kg of rice - Php. 360.00
3kg of pork- Php. 390.00
1kg of rice is Php. 90.00
1kg of pork is Php. 130.00
The height of the telephone pole = 9 / 1.5 = 6 meters
