Answer:
48 meters
Step-by-step explanation:
The first thing is to calculate the scale, since we know both widths it is possible:
we pass the 9 meters to centimeters = 900 cm
900/6 = 150
So the scale would be 1: 150
Which means that the length is 150 times bigger.
10 * 150 = 1500cm or what equals 15m
the perimeter is the sum of all the sides, therefore:
P = 15 + 15 + 9 + 9
P = 48
Which means that the perimeter of the room is 48 meters
Do you have to show ur work?
I'm pretty sure the answer is the top right one because it looks really messed up. i mean, mi/hr*min doesn't equal mi, but im not too sure about the conversion part.
<h3>
The dimensions of the given rectangular box are:</h3><h3>
L = 15.874 cm , B = 15.874 cm , H = 7.8937 cm</h3>
Step-by-step explanation:
Let us assume that the dimension of the square base = S x S
Let us assume the height of the rectangular base = H
So, the total area of the open rectangular box
= Area of the base + 4 x ( Area of the adjacent faces)
= S x S + 4 ( S x H) = S² + 4 SH ..... (1)
Also, Area of the box = S x S x H = S²H
⇒ S²H = 2000

Substituting the value of H in (1), we get:

Now, to minimize the area put :

Putting the value of S = 15.874 cm in the value of H , we get:

Hence, the dimensions of the given rectangular box are:
L = 15.874 cm
B = 15.874 cm
H = 7.8937 cm
55.79 = 0.99<em>d + </em>39.95
55.79 - 39.95 = 15.84
0.99d = 15.84
0.99d/0.99 = 15.84/0.99
d = 16
2) Equation = 12.6 million = 4(x) + 1 million
12.6 million - 1 million = 11.6 million
11.6 million/4 = x
x = 2900000
hope this helps