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3 years ago

PLEASE HELP. ALG 1 EXAM

Mathematics

1 answer:

shutvik [7]3 years ago

3 0

Answer:

W=5 L=22

Step-by-step explanation:

L=3W+7

2L+2W=10W+4

5x3+7 = 22

(((22×2)+(5×2))-4)/10=5

there are more technical ways to solve this but with simple, whole numbers trial and error is the easiest

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Hi there can anyone help me out with this because I'm really struggling with this

kakasveta [241]

I = PRT/100
I = Simple Interest
P = Principal
R = Interest Rate per period
T = Time ( no. of periods )

Interest = (2500×9.5×3)/100 = 712.50

Answer : $2500 - $712.50 = $1787.50

8 0

4 years ago

How do you factor 35x^2+26-16? Show work please.

Sedbober [7]

well, first off, we do a quick prime factoring of the leading term's coefficient, 35, and the constant, 16.

35 = 5*7

16 = 2*2*2*2

and the rest is just a mix and match.

what combination from the factors of 35 and the factors of 16, can provide a product whose sum is the middle term 26? well, without further adieu.

we can try 5*2*2 + 7*2*2, and that's 20 and 28, ok, 28 - 20 is 8, so that won't work.

another can be 5*2*7 and 2*2, that's 70 and 4, 70 - 4 is 56, that won't work either.

5*2*2*2 and 7*2, that's 40 and 14, hmmm 40 - 14 = 26!!! holly guacamole!

so then,

$\bf 35x^2+26x-16\implies (5x-\stackrel{\stackrel{2}{\downarrow }}{2})(7x+\stackrel{\stackrel{2\cdot 2\cdot 2}{\downarrow }}{8})$

3 0

4 years ago

Solve the system by elimination. − 2 x + 2 y + 3 z = 0 − 2 x − y + z = − 3 2 x + 3 y + 3 z = 5

taurus [48]

Answer:

$x=1, y=1, z=0$

Step-by-step explanation:

we have

$-2x+2y+3z=0$ ----> equation A

$-2x-y+z=-3$ -----> equation B

$2x+3y+3z=5$ ----> equation C

adds equation A and equation C

$-2x+2y+3z=0\\2x+3y+3z=5\\-------\\2y+3y+3z+3z=0+5$

$5y+6z=5$ -----> equation D

adds equation B and equation C

$-2x-y+z=-3\\2x+3y+3z=5\\--------\\-y+3y+z+3z=-3+5$

$2y+4z=2$ -----> equation E

we have the system

$5y+6z=5$ -----> equation D

$2y+4z=2$ -----> equation E

Multiply equation E by -1.5 both sides

$-1.5(2y+4z)=-1.5(2)$

$-3y-6z=-3$ -----> equation F

adds equation D and equation F

$5y+6z=5\\-3y-6z=-3\\---------\\5y-3y=5-3\\2y=2\\y=1$

<em>Find the value of z</em>

substitute the value of y in equation E (or substitute in equation D)

$2(1)+4z=2$

$2+4z=2$

$4z=0$

$z=0$

<em>Find the value of x</em>

substitute the value of y and z in equation A (or equation B or C)

$-2x+2(1)+3(0)=0$

$-2x+2=0$

$-2x=-2$

$x=1$

therefore

The solution of the system of equations is

$x=1, y=1, z=0$

4 0

4 years ago

For the first 30 km, the bicyclist rode with a speed of v km/hour. For the remaining 17 km he rode with a speed which was 2 km/h

Alika [10]

If v = 15 km/h We have:

d1 = 30 km

d2 = 17 km

Since speed = distance/time follows time = distance/speed.

The total time of the entire trip is is the sum of the time of the first 30 km and the time of the remaining 17 km:

d1/v + d2/(v + 2) = 30/15 + 17/(15 + 2) = 2 + 1 = 3 hours

The answer is t=3hours

3 0

3 years ago

Read 2 more answers

A humanities professor assigns letter grades on a test according to the following scheme. A: Top 13% of scores B: Scores below t

Musya8 [376]

Answer:

Step-by-step explanation:

Given data:

mean μ = 70.

standard deviation σ, 9.6.

P(Z < 1.123) = 0.13

z = 1.13

Use the z-score formula,

x = z×σ +μ

Substitute the values in the above equation.

x = 1.13 9.6 + 70 = 81

The minimum score required for an A grade is = 81

7 0

3 years ago