Which equation could be used to solve for the measure of side Q in the triangle QRS shown below given...
1 answer:
The image is missing, so i have attached it
Answer:
Equation is;
q/sin 105 = 15/sin 30
Step-by-step explanation:
We are given;
Angle Q = 105°
Angle S = 30°
s = 15
From sine rule we know that;
a/sin A = b/sin B = c/sin C.
Thus, applying that to this question, we can find side q.
Thus;. q/Sin Q = s/Sin S
Plugging in the relevant values to obtain ;
q/sin 105 = 15/sin 30
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Answer:
Step-by-step explanation:
We can answer this in two ways: Differentiation and Graphing.
<u>Differentitate:</u>
The first derivative of a function yields a function that provides the slope for any point on the line of the original function. The slope of a vertex is zero, so we can set the first derivative to 0 and solve for x.
f(x) = 3(x-1)^2 + 4
f(x) = 3(x-1)(x-1) + 4
f(x) = 3(x^2 - 2x + 1) + 4
f(x) = 3x^2 - 6x + 7
f'(x) = 6x -6
Set this = 0 and find x:
0 = 6x -6
x = 1
The value of y when x=1 in the original equation is:
f(1) = 3(1-1)^2 + 4
y = 4
The vertex is (1,4)
<u>Graph:</u>
You can use DESMOS to plot the function. The result is attached. Look for the vertex and read the coordinates. (1,4) seems to work.
