Which equation could be used to solve for the measure of side Q in the triangle QRS shown below given...
1 answer:
The image is missing, so i have attached it
Answer:
Equation is;
q/sin 105 = 15/sin 30
Step-by-step explanation:
We are given;
Angle Q = 105°
Angle S = 30°
s = 15
From sine rule we know that;
a/sin A = b/sin B = c/sin C.
Thus, applying that to this question, we can find side q.
Thus;. q/Sin Q = s/Sin S
Plugging in the relevant values to obtain ;
q/sin 105 = 15/sin 30
You might be interested in
Answers:
10. b.
9. b.
8. a.
7. a.
Step-by-step explanations:
10. Both segments are considered congruent, so turn both expressions into an equation:
Plug this back into the equation to get on both sides.
9. All edges in a square obtain congruent right angles and edges, so set equivalent to the given expression:
8. Both angles are considered supplementary, so turn both expressions into an equation and set it to one hundred eighty degrees:
7. In this rectangle, segment <em>EO</em><em> </em>is a segment bisectour, making these angles <em>Complementary</em><em> </em><em>Angles</em><em>.</em><em> </em>Therefore, set an equation up to find its complement:
I am joyous to assist you at any time.
Answer:
Step-by-step explanation:
The parent function of this graph is: y = sin(x)
The sine function is periodic, meaning it repeats forever.
Standard form of a sine function:
- A = amplitude (height from the mid-line to the peak)
- 2π/B = period (horizontal distance between consecutive peaks)
- C = phase shift (horizontal shift - positive is to the left)
- D = vertical shift
The parent function y = sin(x) has the following:
- Amplitude (A) = 1
- Period = 2π
- Phase shift (C) = 0
- Vertical shift (D) = 0
- Mid-line: y = 0
From inspection of the given graph:
- Amplitude (A) = 1
- Phase shift (C) = 0
- Vertical shift (D) = +3 (as mid-line is y = 3)
Substituting the values into the standard form:
Therefore, the equation of the given trigonometric graph is: