All categories

3 years ago

Find the slope of the line passing through the pair of points. (–4, 5) and (0, 2)

2 answers:

7 0

The equation is (y2-y2)/(x2-x1), making sure to be constistant with which pair is 1 and 2. So let's say (0,2) is 1 and (-4,5) is 2. It looks like this:
(5-2)/(-4-0)=3/(-4)= -3/4 which is your answer

Fed [463]3 years ago

5 0

You would need to draw a graph or get some graph paper and plot those points. Then calculate the rise and the run. Rise is over the run. Then that is your slope. You get the rise by counting how many units up or down it takes to get to the point, and for the run, you count how many units across it is to get to the point. don't forget, if your units are going in a negative direction, then the number will be negative.

You might be interested in

B.<br>Determine the quadratic function given the following zeroes:

Stella [2.4K]

Answer: Read Sol.

Step-by-step explanation: To solve these, call each given zero = z. The function is when given a zero that is an integer (x-z1)(x-z2)(x-z3)... so on until all zeroes are used. This works for fractions also. But when you have irrationals, you will have to make sure each irrational solutions conjugate is there. So if a given zero is 2-sqrt3, then always 2+sqrt3 will also be a 0. Likewise, if given -4-sqrt7, then -4+sqrt7 will also always be a zero. Use this logic to solve them very quickly! I hope this helps!

4 0

3 years ago

Which is equivalent to square root 10^3/4x?

iren2701 [21]

Answer:

5√(10/x)

Step-by-step explanation:

√10^3/4x

= √10^3 / √4x

= 10√10 / 2√x

=(10/2)√(10/x)

= 5√(10/x)

7 0

3 years ago

I need help solving these problems

Delicious77 [7]

QUESTION 1

$4 {p}^{2} = 2 \times 2\times {p} \times p$

QUESTION 2

$39 {b}^{3} {c}^{2} = 3 \times 13 \times {b} \times b \times b\times {c} \times c$

QUESTION 3

$100 {x}^{3} y {z}^{2} = {2} \times 2 \times {5} \times 5 \times {x} \times x \times x\times y \times {z} \times z$

QUESTION 4

$66 {d}^{4} = 2 \times 3 \times 11 \times {d} \times d \times d \times d$

QUESTION 5

$85 {x}^{2} {y}^{2} = 5 \times 17 \times {x} \times x \times {y} \times y$

QUESTION 6

$18xy = 2 \times {3}^{2} \times x \times y$

$36 {y}^{2} = {2}^{2} \times {3}^{2} \times {y}^{2}$

The greatest common factor is the product of the least powers of the common factors;

$GCF=2 \times {3}^{2} \times y$

$GCF=18y$

QUESTION 7

$25mn = {5}^{2} \times m \times n$

$21m = 3 \times 7 \times m$

$GCF=m$

QUESTION 8

$15a = 3 \times 5 \times a$

$28a {b}^{2} = {2}^{2} \times 7 \times a \times {b}^{2}$

$GCF=a$

QUESTION 9

$24 {d}^{2} = {2}^{3} \times 3 \times {d}^{2}$

$30 {c}^{2} d = 2 \times 3 \times 5 \times d$

$GCF=2 \times 3 \times d$

$GCF=6d$

QUESTION 10

$20gh = {2}^{2} \times 5 \times g \times h$

$36 {g}^{2} {h}^{2} = {2}^{2} \times {3}^{2} \times {g}^{2} \times {h}^{2}$

$GCF= {2}^{2} \times g \times h$

$GCF=4gh$

QUESTION 11

$17 {c}^{3} {d}^{2} = 17 \times {c}^{3} \times {d}^{2}$

$5 {c}^{2} {d}^{2} = 5 \times {c}^{2} \times {d}^{2}$

$GCF= {c}^{2} \times {d}^{2}$

$GCF= {c}^{2}{d}^{2}$

4 0

3 years ago

1.)12.5+(-31.5)=<br>2.)-31.91+(-16.7)=<br>3.)1/6+(-11/12)+2/3=<br>4.)29+(-15.7)+(-31.05)=

Xelga [282]

1. = Step 1. Simplify Brackets and you get $12.5 - 31.5$ Step 2. Simplify and you get $-19
$ which is your answer.

2. = Step 1. Simplify Brackets and you get $-31.91-16.7$ Step 2. Simplify and you get $-48.61$

3. = Step 1. Simplify Brackets and you get $\frac{1}{6} - \frac{11}{12} + \frac{2}{3}$ Step 2. Simplify and you get $- \frac{1}{12}$

4. Step 1. = Simplify Brackets and you get $29-15.7-31.05$ Step 2. Simplify and you get $-17.75$

5 0

4 years ago

A store is having a 20% off sale. The sale price of an item with price p is p – 0.2p. What is an equivalent expression?

GuDViN [60]

If it is 20% off, then ur actually paying 80%
so an equivalent expression would be 0.80p

3 0

3 years ago

Read 2 more answers