How could you use doubles to help you find the sum of 7+6

Mathematics

2 answers:

Lina20 [59]3 years ago

7 0

7-6=1
6*2=12
12+1=13 bye

timurjin [86]3 years ago

3 0

Use doubles to multipy. 7*2 is 14 right. Hope I helped.

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What is perimeter of the semi circle?

Nesterboy [21]

Answer:

54.22 mm

Step-by-step explanation:

Find the circumference of the circle and then divide it by 2.

We start with the formula for the circumference for the circle:

C = 2πr

To find r, divide 22 by 2:

22/2=11

Now find the cicumference:

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7 0

3 years ago

Graph the linear equation. Find three points that solve the equation, then plot on the graph.

Illusion [34]

Answers:

Three points that solve the equation: $(1, \frac{19}{4} ) , (2, 5), (3, \frac{21}{4} )$

The graph is shown in the attached pictures.

NOTE: The first picture is the graph of the equation along with the plotted points, and the second one shows the work for those three points.

Step-by-step explanation:

1. To graph this equation, an easier way to do it would be to convert to slope-intercept form so we can graph knowing the y-intercept and the slope. Do this by isolating the y on the left side like so:

$x-4y=-18\\-4y = -x -18\\y = \frac{-x}{-4} -\frac{18}{-4} \\y = \frac{1}{4} x + \frac{9}{2}$

Remember that slope-intercept form is in y = mx + b format, and that m is the slope and b is the y-intercept. With this information, we know that (0, $\frac{9}{2}$ ) is the y-intercept and $\frac{1}{4}$ is the slope of this equation. We can plot the point (0, $\frac{9}{2}$ ) on the graph, and then use the slope of $\frac{1}{4}$ from there to graph other points and form a line. (When I graphed the line, I didn't include these "other points" so it wasn't confusing to locate which points were the three solutions listed.)

2. Points that solve an equation - or solutions - are also points that the line of the equation intersects. So, what we can do is form a table, plug in some x values into the equation, and solve for a y-value. The x and y values will form a point that is on the graph, thus they are solutions. (Please look at the second picture for work and clarification.) After identifying these points, just plot them on the graph and label them (as shown in the first picture).