1. Given any triangle ABC with sides BC=a, AC=b and AB=c, the following are true :
i) the larger the angle, the larger the side in front of it, and the other way around as well. (Sine Law) Let a=20 in, then the largest angle is angle A.
ii) Given the measures of the sides of a triangle. Then the cosines of any of the angles can be found by the following formula:
a^{2}=b ^{2}+c ^{2}-2bc(cosA)
2.
20^{2}=9 ^{2}+13 ^{2}-2*9*13(cosA) 400=81+169-234(cosA) 150=-234(cosA) cosA=150/-234= -0.641
3. m(A) = Arccos(-0.641)≈130°,
4. Remark: We calculate Arccos with a scientific calculator or computer software unless it is one of the well known values, ex Arccos(0.5)=60°, Arccos(-0.5)=120° etc
Answer:
191
Step-by-step explanation:
Sorry it's sideways. I drew a box chart for this. First, fill in what you know: the number of white and black beads Ally has. Then, calculate how many black beads Betty has (Ally's number, 59, minus 35.) 59-35 = 24.
They tell you the total number of beads is 346. Add up Ally's total to get 131, then subtract that from 346. That's Betty's total beads, 215.
Last, subtract the 24 black beads Betty has from the 215 total to get 191.
Velocity
Formula wise:
1/2 x mass x velocity^2
4.5 and 3.25 gets you to 7.75, you are correct
A trapezoid has two parallel sides, but the top one is shorter than the bottom one