Answer:
Step-by-step explanation:
Two ∆s can be considered to be congruent to each other using the Side-Angle-Side Congruence Theorem, if an included angle, and two sides of a ∆ are congruent to an included angle and two corresponding sides of another ∆.
∆ABC and ∆DEF has been drawn as shown in the attachment below.
We are given that and also .
In order to prove that ∆ABC ∆DEF using the Side-Angle-Side Congruence Theorem, an included angle which lies between two known side must be made know in each given ∆s, which must be congruent accordingly to each other.
The included angle has been shown in the ∆s drawn in the diagram attached below.
Therefore, the additional information that would be need is:
Answer : The correct option is (A) 68.
Step-by-step explanation :
As we are given that:
LN = 6x - 5
LM = x + 7
MN = 3x + 20
Now we have to determine the value of MN.
According to the question:
LN = LM + MN
Now putting all the given values in this expression, we get:
6x - 5 = (x + 7) + (3x + 20)
6x - 5 = 4x + 27
6x - 4x = 27 + 5
2x = 32
x = 16
The value of MN = 3x + 20 = 3(16) + 20 = 48 + 20 = 68
Therefore, the value of MN is 68.
Answer:
17/40
Step-by-step explanation:
First let's find the least common denominator. The denominators are 8 and 25 so we need to find the least common multiple of 8 and 25.
8=2*2*2
25=5*5
Since they share no common factors the least common multiple of 8 and 25 is 8*25 which is 200.
Now we convert the fractions:
5/8*25/25=125/200
5/25*8/8=40/200
Then we subtract:
125/200-40/200=85/200
Now we simplify it:
17/40
X = 1/3
4x + 2x - 2 = 0
6x - 2 = 0
+2 +2
6x = 2
/6 /6
X = 1/3