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3 years ago

12

The difference between two rational numbers and get a negative number

1 answer:

expeople1 [14]3 years ago

4 0

2-3 is -1. difference between two rational numbers that make a negative

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What is the value of 5×*5-×

igor_vitrenko [27]

Answer:

It is 25

Step-by-step explanation:

3 0

3 years ago

A quadratic function is defined by \small f\left(x\right)=x^2-8x-4. Which expression also defines \small f and best reveals the

ohaa [14]

Answer:

f(x) = [x – (4 + √20)][x – (4 – √20]

Step-by-step explanation:

In order to know the function that best describes the given f(x) that best reveals it's minimum or maximum, we need to know solve for x.

x² – 8x – 4 = 0

Using completing the square method

x² – 8x = 4

x² – 8x + 4² = 4 + 4²

(x – 4)² = 20

x = 4 ±√20

Therefore

f(x) = [x – (4 + √20)][x – (4 – √20]

6 0

3 years ago

1.) You go skiing on one route with an equation = 2 + 4 and then

CaHeK987 [17]

The best information that describes your routes is the second route was steeper than your first, and the second route was higher up the mountain.

<h3>What is the slope of a linear equation?</h3>

The slope of a linear equation is the change in the rise over the run. So, the slope of a linear equation shows that the larger the slope, the steeper the line becomes.

From the given information:

y = 2x + 4 --- (1)

y = 4x + 1 --- (2)

Using the slope-intercept formula:

y = mx + b

m = slope
b = y-intercept

From the first equation, the slope is 2 and in the second equation, the slope is 4.

Therefore, we can conclude that the second route was steeper than your first, and the second route was higher up the mountain.

Learn more about the slope of a linear equation here:

brainly.com/question/1884491

#SPJ1

3 0

2 years ago

In ΔJKL, the measure of ∠L=90°, KL = 11 feet, and JK = 32 feet. Find the measure of ∠J to the nearest tenth of a degree.

Lady bird [3.3K]

Answer: J = 20.1

Step-by-step explanation:

sin J = hypotenuse/opposite = 11/32

Sin J =11/32

J=sin-1(11/32)

J= 20.1055

4 0

3 years ago

Please help with only the circled ones (1-8)

mixas84 [53]

When you have an exponent divided by another exponent, you subtract the exponents (only when it has the same base)

For example:

$\frac{x^8}{x^3} =x^{8-3}=x^5$

$\frac{x^3}{x^2} =x^{3-2}=x^{1}$

When you have a negative exponent, you move it to the other side of the fraction to make the exponent positive

For example:

$x^{-2}=\frac{1}{x^2}$

$\frac{1}{x^{-5}}=\frac{x^5}{1} = x^5$

$\frac{y^{-2}}{x^{-1}} =\frac{x^1}{y^2} =\frac{x}{y^2}$

1. $\frac{10^{15}}{10^3} =10^{15-3} = 10^{12}$

2. $\frac{(-3)^4}{(-3)^{-3}} =(-3)^{4-(-3)}=(-3)^{4+3} = (-3)^7$

3. $\frac{8}{8^3} =8^{1-3} = 8^{-2}=\frac{1}{8^2}$

4. $\frac{a^{12}}{a^2} =a^{12-2}=a^{10}$

5. $\frac{m^{-2}n^{16}}{m^{4}n^2} =(m^{-2-4})(n^{16-2})=(m^{-6})(n^{14})=\frac{n^{14}}{m^{6}}$

This is one of the ways you could have done it

6. $\frac{p^5q^{-10}}{p^6q^{-2}} =(p^{5-6})(q^{-10-(-2)})=(p^{-1})(q^{-8})=\frac{1}{p^1q^8} =\frac{1}{pq^8}$

7. $\frac{63x^{18}}{9x^{2} }$ Divide 63 and 9

$\frac{7x^{18}}{x^{2}} =(7)(x^{18-2})=(7)(x^{16})=7x^{16}$

8. $\frac{28r^4}{-7r^{15}} =(\frac{28}{-7} )(r^{4-15})=(-4)(r^{-11})=(-4)(\frac{1}{r^{11}} )=\frac{-4}{r^{11}}$

[More information with exponents]

If you multiply an exponent directly with another exponent, you multiply the exponents together

For example:

$(x^{2})^4=x^{2(4)}=x^8$

$(x^{3})^5 =x^{3(5)}=x^{15}$

If you multiply a variable with an exponent by a variable with an exponent, you add the exponents

For example:

$(x^{2}) (x^6)=x^{2+6}=x^8$

$(x^{3})(x^1)=x^{3+1}=x^4$

3 0

3 years ago