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3 years ago

HELP ME ASAP PLEASEEE!!! Work out the size of angle x. 20° 165° 33°

Mathematics

2 answers:

Tcecarenko [31]3 years ago

6 0

The answer is x = 52 angle

german3 years ago

3 0

Answer:

52 degrees

Step-by-step explanation:

add all the known angles together, then subtract it from 360

360=x+33+20+90+165

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Miranda's math certificate is 8 inches tall and 13 inches wide. Miranda wants to put the certificate in a fancy frame that costs

Dvinal [7]

He answer hence would be 104

7 0

3 years ago

What number is 9.5% of 20?

mars1129 [50]

1.9

9.5% = 0.095

0.095* 20 = 1.9

7 0

3 years ago

F(x) = x^2 + 4x + 20 find the real roots. take your time if you want :)

s344n2d4d5 [400]

Answer:

No real roots

$x = -2 + 4i, x = -2 - 4i$

Step-by-step explanation:

Hello!

We can solve the quadratic by using the Quadratic Formula.

Standard form of a Quadratic: $ax^2 + bx + c = 0$

Quadratic Equation: $x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}$

Given our Equation: $f(x) = x^2 + 4x + 20$

a = 1
b = 4
c = 20

Set the equation to 0 and solve using the formula.

<h3>Solve</h3>

$x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}$
$x = \frac{-4\pm\sqrt{4^2 - 4(1)(20)}}{2(1)}$
$x = \frac{-4\pm\sqrt{16 - 80}}{2}$
$x = \frac{-4\pm\sqrt{-64}}{2}$
$x = \frac{-4\pm8i}{2}$
$x = -2 + 4i, x = -2 - 4i$

There are no real roots to the quadratic.

8 0

2 years ago

The coordintates of 2 vertices arae A (-2,5), and B(5,-3). What could be the other vertices to this right triangle?

Alecsey [184]

The other vertices are (-2,5).

6 0

3 years ago

I need help, urgently.

Korvikt [17]

Answer:

y = -0.5(x - 4)^2 + 5.

y = -0.5x^2 + 4x - 3.

Step-by-step explanation:

The vertex is at (4, 5). so we have:

f(x) = a(x - 4)^2 + 5

When x = 0 y = -3 so substituting in the above:

- 3 = a(0-4)^2 + 5

-8 = 16a

a = -0.5.

So the vertex form is y = -0.5(x - 4)^2 + 5.

Standard form:

y = -0.5(x^2 - 8x + 16) + 5

y = -0.5x^2 + 4x - 8 + 5

y = -0.5x^2 + 4x - 3.

5 0

3 years ago