Xavier's bowling average is 185.4 and Lola's average is 122.9. About how many times greater is Xavier's average than Lola's?

Mathematics

2 answers:

Lena [83]2 years ago

8 0

Hello!

To find how many times greater his average is, we just divide.

185.4/122.9≈1.51

Therefore, his average is about 1.51 times greater than Lola's.

I hope this helps!

stich3 [128]2 years ago

8 0

Hi. It is 62.5 times greater

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