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levacccp [35]
3 years ago
7

**BRAINLIEST AVAILABLE**** PLEASE HELP ME WITH THIS!!!

Mathematics
2 answers:
Anika [276]3 years ago
4 0

Answer:

E.

Step-by-step explanation:

Even though we have a sample of 40 units, we cannot determine that the units that are not in the sample will have the same or similar quality as the units that are in the sample. Thus none of the conclusions can be true.

omeli [17]3 years ago
4 0

Answer: Choice B) 100 pieces must be defective

Assuming the sample selected is representative of the population, we have two copies of "25" in that list (row 4; row 8) out of 40 total. So 2/40 = 1/20 = 0.05 = 5% of the items should be defective out of the entire population. Again this is assuming the sample is representative.

So we take 5% of 2000 and we end up with 0.05*2000 = 100 items we expect to be defective from a sample of 2000 items. Keep in mind that the true count will probably not be 100 items but some value close around it (eg: 98 or 101). This value is an estimate and not always perfect.

If choice B said "around 100" or "about 100" or "approximately 100" then I think it would be more technically correct. I think this is what your teacher is after.

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Lady_Fox [76]

<em>Answer: </em>

<em>A = $7,350.00</em>

<em></em>

<em>Step-by-step explanation:</em>

<em>Equation:</em>

<em>A = P(1 + rt)</em>

<em>First, converting R percent to r a decimal</em>

<em>r = R/100 = 9%/100 = 0.09 per year.</em>

<em>Putting time into years for simplicity,</em>

<em>30 months / 12 months/year = 2.5 years.</em>

<em></em>

<em></em>

<em>Solving our equation:</em>

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<em>A = $7,350.00</em>

<em>The total amount accrued, principal plus interest, from simple interest on a principal of $6,000.00 at a rate of 9% per year for 2.5 years (30 months) is $7,350.00.</em>

<em>* Therefor, the answer is $7,350.00.</em>

<em>* Hopefully this helps:) Mark me the brainliest:)!!!</em>

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3 years ago
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Answer:

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Given that a cat is to receive 90 kcal of a canned food at each meal, and the food has a caloric density of 450 kcal per can, to determine what fraction of a can it should receive at each meal, the following calculation must be performed:

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