All categories

3 years ago

What is 7 5/6 as im improper fraction?

Mathematics

2 answers:

Anettt [7]3 years ago

7 0

Answer:

The answer is 47/6

Step-by-step explanation:

sertanlavr [38]3 years ago

7 0

7*6/6+5/6
7*6/6+5/6
7*6*5/6
Answer:
=47/6

You might be interested in

Choose the correct symbol from the drop-down list to compare the rational number

Kay [80]

Answer:

Step-by-step explanation:

If we plot -1.5 and -1.76, we would see thant -1.5 is to the right of -1.76

Right means larger here, so -1.5 is larger

3 0

3 years ago

Read 2 more answers

Help please!

Anna71 [15]

Answer:

y= -4x^2 + 15x - 14

Step-by-step explanation:

A parabola is always in the form y = ax^2 + bx + c.

Substitute each point to produce different equations:

-14 = 0a + 0b + c = c

so c = -14

-3 = a1^2 + b1 + c = a + b - 14

so a + b = 11

0 = a2^2 + b2 + c = 4a + 2b -14 = 0

so 4a + 2b = 14

if we double a + b = 11 we get 2a + 2b = 22

Subtract this from 4a + 2b = 14 and we get 2a = -8 so a= -4 and b = 11 - a = 15

We don't need to use the (3,5) points as we have all the information we need.

4 0

3 years ago

Read 2 more answers

For a certain river, suppose the drought length Y is the number of consecutive time intervals in which the water supply remains

AnnZ [28]

Answer:

a) There is a 9% probability that a drought lasts exactly 3 intervals.

There is an 85.5% probability that a drought lasts at most 3 intervals.

b)There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

Step-by-step explanation:

The geometric distribution is the number of failures expected before you get a success in a series of Bernoulli trials.

It has the following probability density formula:

$f(x) = (1-p)^{x}p$

In which p is the probability of a success.

The mean of the geometric distribution is given by the following formula:

$\mu = \frac{1-p}{p}$

The standard deviation of the geometric distribution is given by the following formula:

$\sigma = \sqrt{\frac{1-p}{p^{2}}$

In this problem, we have that:

$p = 0.383$

$\mu = \frac{1-p}{p} = \frac{1-0.383}{0.383} = 1.61$

$\sigma = \sqrt{\frac{1-p}{p^{2}}} = \sqrt{\frac{1-0.383}{(0.383)^{2}}} = 2.05$

(a) What is the probability that a drought lasts exactly 3 intervals?

This is $f(3)$

$f(x) = (1-p)^{x}p$

$f(3) = (1-0.383)^{3}*(0.383)$

$f(3) = 0.09$

There is a 9% probability that a drought lasts exactly 3 intervals.

At most 3 intervals?

This is $P = f(0) + f(1) + f(2) + f(3)$

$f(x) = (1-p)^{x}p$

$f(0) = (1-0.383)^{0}*(0.383) = 0.383$

$f(1) = (1-0.383)^{1}*(0.383) = 0.236$

$f(2) = (1-0.383)^{2}*(0.383) = 0.146$

Previously in this exercise, we found that $f(3) = 0.09$

$P = f(0) + f(1) + f(2) + f(3) = 0.383 + 0.236 + 0.146 + 0.09 = 0.855$

There is an 85.5% probability that a drought lasts at most 3 intervals.

(b) What is the probability that the length of a drought exceeds its mean value by at least one standard deviation?

This is $P(X \geq \mu+\sigma) = P(X \geq 1.61 + 2.05) = P(X \geq 3.66) = P(X \geq 4)$ .

We are working with discrete data, so 3.66 is rounded up to 4.

Either a drought lasts at least four months, or it lasts at most thee. In a), we found that the probability that it lasts at most 3 months is 0.855. The sum of these probabilities is decimal 1. So:

$P(X \leq 3) + P(X \geq 4) = 1$

$0.855 + P(X \geq 4) = 1$

$P(X \geq 4) = 0.145$

There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

8 0

4 years ago

Two adjacent supplementary angles form a

Sedbober [7]

Obtuse because it all adds up to 180 degrees <span />

4 0

3 years ago

4 is the _____ of 4n

murzikaleks [220]

Answer:

4 is the coefficient of 4n

Step-by-step explanation:

8 0

3 years ago