How many solutions does the following equation have -14(z-5)=-14z+70

Mathematics

1 answer:

Nookie1986 [14]3 years ago

6 0

Answer:

The given equation has NO solutions

Step-by-step explanation:

Given equation as :

- 14 (z - 5) = - 14 z + 70

Or, - 14 z + 70 = - 14 z + 70

Since the coefficient of variable z is same on both side i.e ( - 14 ) , So , the Given equation has NO - solution .

Hence the given equation has NO solutions Answer

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In triangle FGH, GJ is an angle bisector of ∠G and perpendicular to FH.

Citrus2011 [14]

The picture in the attached figure

we know that
If line GJ bisects the angle FGH, that means we also know that the angle FGH is divided into two equal sizes.

Now, we have
Angle FGJ = Angle HGJ
Angle GJF = Angle GJH
This information means that angle GHJ = angle GFJ

We have two congruent right-angled triangle
We can then further deduce that
Side GF = Side GH
Since triangle FGJ and triangle GJH are congruent,
then
side FJ equals to side JH
3x-8=16
3x=16+8
3x=24
x=8 units
Hence,
the length of FH = 2×8=16 units

the answer is
FH=16 units