8sr6 + 2sr2×2×3 +5sr3 - sr2×3×3×3
=8sr6 + 2(2)sr3 + 5sr3 - 3sr2×3
=8sr6 + 4sr3 + 5sr3 - 3sr6
=8sr6 - 3sr6 + 4sr3 +5sr3
=5sr6 + 9sr3 (ans)
9514 1404 393
Answer:
Step-by-step explanation:
The cost of each plan (y) is the sum of the initial fee and the product of the mileage charge and the number of miles (x).
First Plan: y = 40 +0.13x
Second Plan: y = 53 +0.08x
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We can find when the costs are the same by solving this system of equations. A way to do that is to subtract the second equation from the first:
(y) -(y) = (40 +0.13x) -(53 +0.08x)
0 = -13 +0.05x
Multiplying by 20 gives ...
0 = -260 +x
Adding 260, we have ...
x = 260
The plans cost the same for 260 miles of driving.
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The cost of the plans for that distance is ...
y = 40 +0.13x = 40 +0.13(260) = 40 +33.80
y = 73.80
The cost when the two plans cost the same is $73.80.
In this question, you're solving for a.
Solve for a:
-8(1 - a) =-7 -(1 - 3a)
<em>use the distributive property</em>
-8 + 8a = -7 -(1 - 3a)
-8 + 8a = -7 - 1 + 3a
<em>combine like terms</em>
-8 + 8a = -8 + 3a
<em>subtract 3a from both sides</em>
-8 + 5a = -8
<em>add 8 to both sides</em>
5a = 0
<em>divide both sides by 5</em>
a = 0