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3 years ago

Due in 30 min plz Help! Order the Sides from LEAST TO GREATEST

Mathematics

2 answers:

Vlad [161]3 years ago

7 0

Answer:

BC, AB, AC

Step-by-step explanation:

Let's first find m∠BAC, which is 180° - ( 95° + 55° )

(interior angle theorem)

That equals 30°.

Now that we know all of the angles, we can order the sides.

Each side in a triangle is as big as its corresponding angle (opposite angle), so the bigger the opposite angle, the larger the side, and vice versa.

Since ∠BAC is the least, its corresponding side, BC will also be the smallest. Next is ∠ACB at 55°, so side AB is the medium sized side. Finally at 95°, ∠ABC is the greatest angle, putting its opposite side, AC at the greatest.

Alona [7]3 years ago

6 0

I believe the answer is BC, AB, AC

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A rhombus ABCD has AB = 10 and m∠A = 60°. Find the lengths of the diagonals of ABCD.

melisa1 [442]

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1. the diagonals of a rhombus bisect each other
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First, we can let O be the point where the two diagonals intersect (as shown in the attached image). Using the properties listed above, we can conclude that ∠AOB is equal to 90° and ∠BAO = 60/2 = 30°.

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$\overline{OB}:\overline{AB} = 1:2$
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$\overline{AD} = 2(\overline{AO}) = 10\sqrt{3}$
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