933.33 x 933.33 is ypur answer to maximize area
This is an equation in STANDARD form for a circle:
(x-h)^2 + (y-k)^2 = r^2
The values of (h, k) are the center point of the circle. When they are put into an equation, their symbols flip as in, if they are positive on a graph, they become negative in the equation and vice versa.
The value (r) is the radius and is squared in the equation. In this case, the square root of 1 is 1.
(x)^2 + (y-6)^2 = 1
Answer:
Step-by-step explanation:
Start by factoring out a 5:
We need to find two integers that have a product of 12, and a sum of -7:
(-3)(-4)=12
-3-4=-7
We can split -7x into -3x and -4x
Factor each half separately:
![5[x(x-3)-4(x-3)]](https://tex.z-dn.net/?f=5%5Bx%28x-3%29-4%28x-3%29%5D)
Since x and -4 are both being multiplied by x-3, we can combine them:
Answer:
Last one: Symmetric with respect to the y-axis
Step-by-step explanation:
About the Y-AXIS
because think about using a few points x = -2, x = -1 , x = 1, x = 2
notice that 2*(-2)^4 = 2 *(2)^4
and 2*(-1)^4 = 2*(1)^4
Answer:
x = 12
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
g(x) = 1/2x - 11
g(x) = -5
<u>Step 2: Solve for </u><em><u>x</u></em>
- Substitute: -5 = 1/2x - 11
- Isolate <em>x</em> term: 6 = 1/2x
- Isolate <em>x</em>: 12 = x
- Rewrite: x = 12
