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victus00 [196]
3 years ago
11

HELP ME PLZZZ ASAP!

Mathematics
2 answers:
Katyanochek1 [597]3 years ago
5 0

Answer:

6 - 2t < -4

Step-by-step explanation:

:)

riadik2000 [5.3K]3 years ago
4 0

Answer:

what do you mean

Step-by-step explanation:

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Help me PLZ with the exact answer
olchik [2.2K]
Y = 4/-3 - 1

The slope can either be -4/3 or 4/-3 and the y-intercept is (0,1)
4 0
3 years ago
A clothing store has a section of jeans on sale. There is a 30% chance of picking a pair with a 30-inch inseam; a 25% chance of
Andrej [43]

The expected value of the inseam length of the jeans is found as

30% of 30+ 25% of 32+ 10% of 34+ 10% of 36 + 10% of 38 + 15% of 40

= \frac{30}{100}\times30 +\frac{25}{100}\times32+ \frac{10}{100}\times34+ \frac{10}{100}\times36 +\frac{10}{100}\times38+ \frac{15}{100}\times40

= 9+8+3.4+3.6+3.8+6=33.8

Hence, the third option 33.8 is the correct expected value.

3 0
3 years ago
Justify each step with an algebraic property. 16+x=12
lana [24]
-4 would be the correct answer to the problem
6 0
3 years ago
Read 2 more answers
What is the cross-sectional area of a wire if its outside diameter is 0.0625 inch?
Leno4ka [110]

Given that the diameter: d= 0.0625 inch.

So, radius of the wire : r = \frac{0.0625}{2} = 0.03125 inch

Now the formula to find the cross-sectional area of wire ( circle) is:

A = πr²

= 3.14 * (0.03125)² Since, π = 3.14 and r = 0.03125

=3.14 * 0.000976563

= 0.003066406

= 0.00307 (Rounded to 5 decimal places).

Hence, cross-sectional area of a wire is 0.00307 square inches.

Hope this helps you!

5 0
3 years ago
Read 2 more answers
Find an explicit formula for the arithmetic sequence 12, 5, -2, -9,...
Vadim26 [7]

Answer:

an = 12 -7(n-1)

an = 19-7n

Step-by-step explanation:

The explicit formula for an arithmetic sequence is

an = a1 +d(n-1) where a1 is the first term and d is the common difference

a1 =12

We find d by taking the second term and subtracting the first term

d = 5-12

d = -7

an = 12 -7(n-1)

We can simplify this

an = 12 -7n+7

an = 19-7n

4 0
3 years ago
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