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o-na [289]
3 years ago
5

Sickle cell anemia is a genetic blood disorder where red blood cells lose their flexibility and assume an abnormal, rigid, �sick

le� shape, which results in a risk of various complications. If both parents are carriers of the disease, then a child has a 25% chance of having the disease, 50% chance of being a carrier, and 25% chance of neither having the disease nor being a carrier. If two parents who are carriers of the disease have 3 children, what is the probability that
(a) two will have the disease? (b) none will have the disease?

(c) at least one will neither have the disease nor be a carrier? (d) the first child with the disease will the be 3rd child?
Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
5 0

Answer:

Step-by-step explanation:

Given that,

  • p ( probability that the child has disease) = 25% = 0.25
  • n = number of children = 3

The probability mass function of binomial distribution is,

  • (P = X) = (nCx) X (p)^x X (1 - p)^n-x ; x = 0, 1, 2 ,3
  • = 3Cx X (0.25)^x X (1 - 0.25)^3-x ; ( n = 3, p = 0.25

a) P ( two will have disease)

p ( X = 2) = 3C2 X (0.250^2 X (1 - 0.25) ^3-2

= 0.1406

b) P ( none will have disease)

p (X = 0) = 3C0 X (0.25)^0 X (1 - 0.25)^3-0

= 0.4219

c) P (neither having the disease nor being a carrier) = 25% = 0.25

The probability that at least one will neither having the disease nor being a carrier ;

P(X> or equals to) = 1 - P(X < 1)

= 1 - P( X = 0)

= 1 - 3C0 X (0.25)^0 X (1 - 0.25)^3-0

= 0.5781

d) p( the first child with the disease will the be 3rd child)

P(X = x) = (1-p)^x-1 X p

p( X= x) = ( 1 - 0.25 )^x -1 X 0.25

for third child = P(X = 3) = (1 - 0.25)^3-1 X (0.25)

= 0.1406

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Thanks for any help provided to me! :3
enyata [817]

Answer:

0.25

Step-by-step explanation:

Average means \frac{total \: number}{number \:  \: of  \: \: individuals}

According to the formula, each student in Mr. Goldwasser's class read

\frac{66}{24}  = 2.75

books on average, and each student in Mr. Welch's class read

\frac{65}{26}  = 2.5

books on average.

Therefore, the answer will be

2.75 - 2.5 = 0.25

7 0
3 years ago
Can somebody help me, please?
Lubov Fominskaja [6]

Answer:  x = 9.6

=========================================================

Explanation:

We have two smaller right triangles that are glued together so to speak.

The base of the smaller triangle on the left is 5 while the height is h.

Let's use the tangent rule to find the value of h

tan(angle) = opposite/adjacent

tan(55) = h/5

5*tan(55) = h

h = 5*tan(55)

h = 7.14074003371058

Make sure your calculator is in degree mode. That value of h above is approximate.

--------------------------

Now focus on the smaller triangle on the right

It has the same height value h. This side is the adjacent side while x is the hypotenuse.

We'll use the cosine ratio

cos(angle) = adjacent/hypotenuse

cos(42) = h/x

cos(42) = 7.14074003371058/x

x*cos(42) = 7.14074003371058

x = 7.14074003371058/cos(42)

x = 9.6088135029715

x = 9.6

4 0
3 years ago
And a triangle.
luda_lava [24]

Answer:

Sorry to not actually answer the question, you can just ignore me but no one can answer since you didnt give the full problem, which would be the measurments of the project etc.

3 0
2 years ago
Find the amount erica owes at the end of 6 years if $60000 is loaned to her at a rate of 4% compounded monthly
RSB [31]

Answer: $76,244.51

Step-by-step explanation:

You need to use the compound interest formula here.

First of all however, you need to convert the terms to monthly figures because the interest is compounded monthly.

4% in months = 4 / 12 = 4/12%

6 years = 6 * 12 = 72 months

Now use the compound interest formula:

= Amount * (1 + rate) ^ number of years

= 60,000 * ( 1 + 4/12%) ⁷²

= $76,244.51

4 0
3 years ago
Find an equation of the plane that contains the points p(5,−1,1),q(9,1,5),and r(8,−6,0)p(5,−1,1),q(9,1,5),and r(8,−6,0).
topjm [15]
Given plane passes through:
p(5,-1,1), q(9,1,5), r(8,-6,0)

We need to find a plane that is parallel to the plane through all three points, we form the vectors of any two sides of the triangle pqr:
pq=p-q=<5-9,-1-1,1-5>=<-4,-2,-4>
pr=p-r=<5-8,-1-6,1-0>=<-3,5,1>

The vector product pq x pr gives a vector perpendicular to both pq and pr.  This vector is the normal vector of a plane passing through all three points
pq x pr
=
  i   j   k
-4 -2 -4
-3  5  1
=<-2+20,12+4,-20-6>
=<18,16,-26>

Since the length of the normal vector does not change the direction, we simplify the normal vector as
N = <9,8,-13>

The required plane must pass through all three points.
We know that the normal vector is perpendicular to the plane through the three points, so we just need to make sure the plane passes through one of the three points, say q(9,1,5).

The equation of the required plane is therefore
Π :  9(x-9)+8(y-1)-13(z-5)=0
expand and simplify, we get the equation
Π  :  9x+8y-13z=24

Check to see that the plane passes through all three points:
at p: 9(5)+8(-1)-13(1)=45-8-13=24
at q: 9(9)+8(1)-13(5)=81+9-65=24
at r: 9(8)+8(-6)-13(0)=72-48-0=24
So plane passes through all three points, as required.

3 0
3 years ago
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