Question

Write y=-3(x-7)^2-8 in vertex form

Answer 1

It's in the verex form:

$f(x)+a(x-h)^2+k\\\\(h,\ k)-vertex$

$y=-3(x-7)^2-8\\\\(7,\ -8)-vertex$

Answer 2

Answer:

• The given equation is already in vertex form.

• The vertex is located  at (7,-8)

Step-by-step explanation:

We Know that a standard form of a quadratic equation is given by:

                  $y=ax^2+bx+c$

where a,b and c are real numbers

and the vertex form is given by:

                 $y=a(x-h)^2+k------------------(1)$

where the vertex of the function is at: (h,k)

Here we have the function as:

          $y=-3(x-7)^2-8$

We observe that the equation matches the equation as in equation (1) ; such that a= - 3, h=7 and k= -8

Hence, the equation is already in vertex form and the vertex is at (7,-8)