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finlep [7]
3 years ago
7

Write y=-3(x-7)^2-8 in vertex form

Mathematics
2 answers:
Veronika [31]3 years ago
7 0

It's in the verex form:

f(x)+a(x-h)^2+k\\\\(h,\ k)-vertex

y=-3(x-7)^2-8\\\\(7,\ -8)-vertex

GalinKa [24]3 years ago
4 0
<h2>Answer:</h2>
  • The given equation is already in vertex form.
  • The vertex is located  at (7,-8)
<h2>Step-by-step explanation:</h2>

We Know that a standard form of a quadratic equation is given by:

                  y=ax^2+bx+c

where a,b and c are real numbers

and the vertex form is given by:

                 y=a(x-h)^2+k------------------(1)

where the vertex of the function is at: (h,k)

Here we have the function as:

          y=-3(x-7)^2-8

We observe that the equation matches the equation as in equation (1) ; such that a= - 3, h=7 and k= -8

Hence, the equation is already in vertex form and the vertex is at (7,-8)

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