It can’t be a mixed number
Treat x^4 as the square of p: x^4 = p^2.
Then x^4 - 5x^2 - 36 = 0 becomes p^2 - 5p - 36 = 0.
This factors nicely, to (p-9)(p+4) = 0. Then p = 9 and p = -4.
Equating 9 and x^2, we find that x=3 or x=-3.
Equating -4 and x^2, we see that there's no real solution.
Show that both x=3 and x=-3 are real roots of x^4 - 5x^2 - 36 = 0.
5*( -3.4k ) + 5*( - 7 ) + 3k + 12 = - 17k + 3k - 35 + 12 = -14k - 23 ;
Answer:
76.32
Step-by-step explanation:
Move the decimal point two times to the left 48. --> .48
Multiply .48 by 159
= 76.32
The sign would be negative
X is in the negative area meaning that when x/y and multiplied by y, it would stay negative since y is positive
