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3 years ago

Why was Gutenberg's printing press such an important invention?

2 answers:

7 0

His printing press has been widely considered the most important invention of the modern era because it profoundly impacted the transmission of knowledge. To answer your question, it was because books could be printed faster and easier because they used to have to be written by hand.

kompoz [17]3 years ago

3 0

Answer:

C. Books could be printed faster and easier.

You might be interested in

Evaluate 0.3y + y/z when y = 10 and z = 5

maxonik [38]

Answer:

I think the answer is 5

Step-by-step explanation:

3+2=5

4 0

3 years ago

What is an advantage of using a checking account

horsena [70]

I have to say b. Hope this helps!!! Brainleist Please I only need two more

8 0

3 years ago

A stadium has 48,000 seats. Seats sell for $25 in Section A, $20 in Section B, and $15 in Section C. The number of seats in

Ira Lisetskai [31]

I had a super-ugly equation that didn’t work, but it got me close. (24,000/12,000/12,000 or so)
Then I adjusted the numbers to make the money work.

I’m sorry I can’t help more.

24,000(25) + 14,200(20) + 9,800(15)
= 600,000 + 284,000 + 147,000 = 1,031,000

Section A = 24,000 seats
Section B = 14,200 seats
Section C = 9,800 seats

14,200 + 9,800 = 24,000 seats

5 0

2 years ago

Simplify the following surd expressions<br> a) 7/3 - 2/3 + V3 - 3V3

Nata [24]

Answer:

$\frac{7}{3}-\frac{2}{3}+\sqrt{3}-3\sqrt{3}=\frac{5}{3}-2\sqrt{3}$

Step-by-step explanation:

Given the expression

$\frac{7}{3}\:-\:\frac{2}{3}\:+\:v^3\:-\:3v^3$

solving the expression

$\frac{7}{3}\:-\:\frac{2}{3}\:+\:\sqrt{3}-3\sqrt{3}$

combine the fractions i.e $\frac{7}{3}-\frac{2}{3}=\frac{5}{3}$

$\frac{7}{3}\:-\:\frac{2}{3}\:+\:\sqrt{3}-3\sqrt{3}=\frac{5}{3}+\sqrt{3}-3\sqrt{3}$

add similar elements i.e $\sqrt{3}-3\sqrt{3}=-2\sqrt{3}$

$=\frac{5}{3}-2\sqrt{3}$

Thus,

$\frac{7}{3}-\frac{2}{3}+\sqrt{3}-3\sqrt{3}=\frac{5}{3}-2\sqrt{3}$

4 0

3 years ago

A certain restaurant offers 8 different salads, 5 different main courses, 6 different desserts. If customers choose one salad, o

Naddika [18.5K]

Answer: E. 1200

Step-by-step explanation:

Given : A certain restaurant offers 8 different salads, 5 different main courses, 6 different desserts.

i.e. No. of choices for different salads= 8 -----(1)

No. of choices for different main courses = 5 ----(2)

No. of choices for different desserts = 6

When we choose two different desserts then we use permutation(repeatition not allowed) :

$^6P_2=\dfrac{6!}{(6-2)!}=\dfrac{6\times5\times4!}{4!}=6\times5=30$ ----(3)

[∵ No. of ways to choose r things out of n = $^nP_r=\dfrac{n!}{(n-r)!}$ ]

If customers choose one salad, one main course and two different desserts for their meal , then By Fundamental principle of counting (Multiply (1) , (2) and (3)), the number of different meals are possible :-

$8\times5\times30\\\\=1200$

Hence, the correct answer is E. 1200 .

8 0

3 years ago