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vova2212 [387]
4 years ago
10

What is the solution to –4(8 – 3x) ≥ 6x – 8?

Mathematics
2 answers:
Elza [17]4 years ago
6 0

Answer:

x ≥ 4

Step-by-step explanation:

4(8 - 3x) ≥ 6x - 8  distribute parenthesis on left side

32 + 12x ≥ 6x - 8 (subtract 6x from both sides)

32 + 6x ≥ - 8 (add 32 to both sides)

6x ≥ 24 (divide both sides by 6)

= x ≥ 4

AleksandrR [38]4 years ago
5 0

Answer:

x ≥ 4

Step-by-step explanation:

Given

- 4(8 - 3x) ≥ 6x - 8 ← distribute parenthesis on left side

- 32 + 12x ≥ 6x - 8 ( subtract 6x from both sides )

- 32 + 6x ≥ - 8 ( add 32 to both sides )

6x ≥ 24 ( divide both sides by 6 )

x ≥ 4

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What are the integer solutions to the inequality below?<br><br> 4x+1&lt;5x≤3(x+2)
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Given:

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To find:

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Solution:

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This compound inequality can be written as two separate inequalities 4x+1 and 5x\leq 3(x+2).

Now,

1

1                 ...(i)

And,

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1

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3 years ago
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When drawing the arcs in order to bisect a line segment, why must the width of the compass be more than half of the length of
Aleonysh [2.5K]

Answer: Choice A

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Check out this link to see my response to the identical question answered 2 days ago

brainly.com/question/17191122

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Find the 16th term of the arithmetic sequence whose common difference is d=6 and whose first term is a1=1.
sertanlavr [38]

Answer:

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3 years ago
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