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vova2212 [387]
3 years ago
10

What is the solution to –4(8 – 3x) ≥ 6x – 8?

Mathematics
2 answers:
Elza [17]3 years ago
6 0

Answer:

x ≥ 4

Step-by-step explanation:

4(8 - 3x) ≥ 6x - 8  distribute parenthesis on left side

32 + 12x ≥ 6x - 8 (subtract 6x from both sides)

32 + 6x ≥ - 8 (add 32 to both sides)

6x ≥ 24 (divide both sides by 6)

= x ≥ 4

AleksandrR [38]3 years ago
5 0

Answer:

x ≥ 4

Step-by-step explanation:

Given

- 4(8 - 3x) ≥ 6x - 8 ← distribute parenthesis on left side

- 32 + 12x ≥ 6x - 8 ( subtract 6x from both sides )

- 32 + 6x ≥ - 8 ( add 32 to both sides )

6x ≥ 24 ( divide both sides by 6 )

x ≥ 4

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Answer:

D it is d my guy you have fun with that

4 0
3 years ago
What is the surface area of a cone that has a radius of 8 feet and a slant height of 12 feet? (Use 3.14 for π.)
kodGreya [7K]

Answer:

Surface area of cone is 502.4\ ft^2

Step-by-step explanation:

Given:

radius of a cone (r) = 8 feet

slant height of cone (l) = 12 feet

We need to find the surface area of cone.

Total surface area of cone = Area of circle + Area of curved surface

Now we know that,

Area of circle = \pi r^2

Area of curved surface = \pi rl

Hence Total surface area of cone = \pi r^2+\pi rl=\pi r(r+l) = 3.14 \times 8 (8+12)=3.14\times8\times20= 502.4 \ ft^2

Surface area of cone is 502.4\ ft^2.

4 0
3 years ago
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3 years ago
A runner moves 8 miles every 1 minute. Write and graph an equation in two variables that shows the relationship between time and
Mila [183]

Answer:

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Step-by-step explanation:

5 0
3 years ago
Start with the logistic equation dx dt kx(M−x). Suppose we modify our harvesting. That is we will only harvest an amount proport
Marina CMI [18]

Answer:

a) dx/dt = kx*(M - h/k - x)

Step-by-step explanation:

Given:

- The harvest differential Equation is:

                            dx/dt = kx*(M-x)

Suppose that we modify our harvesting. That is we will only harvest an amount proportional to current population.In  other  words  we  harvest hx per  unit  of  time  for  some h > 0

Find:

a) Construct the differential equation.  

b) Show that if kM > h, then the equation is still logistic.

c) What happens when kM < h?

Solution:

- The logistic equation with harvesting that is proportional to population is:

                               dx/dt = kx*(M-x) hx

It can be simplified to:

                              dx/dt = kx*(M - h/k - x)

- If kM > h, then we can introduce M_n=M -h/k >0, so that:

                              dx/dt = kx*(M_n  - x)  

Hence, This equation is logistic because M_n >0

- If kM < h,  then M_n <0. There are two critical points x= 0 and x = M_n < 0. Since, kx*(M_n  - x)  < 0 for all x<0 then the population will tend to zero for all initial conditions

6 0
3 years ago
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