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3 years ago

How do I solve the second question?

Mathematics

1 answer:

Assoli18 [71]3 years ago

3 0

I have attached a picture showing you how to solve it. I hope that helps.

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can someone help me with this please

steposvetlana [31]

Answer:

7.5

5×1.5=7.5

....................

7 0

3 years ago

Solve the system of linear equations below y=-2x+19 y=x+7

Julli [10]

<span>A) y=-2x+19
B) y=x+7 Multiplying B) by -1
B) -y = -x -7 then adding it to A)
A) y = -2x + 19
3x = 12
x = 4
y = 11

</span>

3 0

3 years ago

Read 2 more answers

Mrs. Brown is a social worker with a salary of $26000 per year. She also works 10 hours per week part-time on weekends at a reta

Masteriza [31]

26,000 + 10(52)(7.5) + 0.10(25,000) =
26,000 + 3900 + 2500 =
32,400 <== total early income

3 0

3 years ago

If a line has a slope of -8/9 a line that is perpendicular has a slope of what

miss Akunina [59]

9/8

Explanation: a perpendicular slope is the opposite of what the normal slope was before

5 0

3 years ago

---- PLEASE HELP <3 .. with steps :( <3

Zielflug [23.3K]

1) 6, 18, 54

2) 5/3, 14/9, 41/27

3) 1.5, 2.5, 2.5

Step-by-step explanation:

The function that we have in this problem is

$g(x)=3x$

We want to find the first 3 iterations.

The initial value is:

x = 2

To find the value of the 1st iteration, we just substitute this value into the expression of the function, and we get:

$g_1(x)=3x=3\cdot 2 = 6$

The to find the value of the 2nd iteration, we just substitute this value into the expression of the function, and we get:

$g_2(x)=3\cdot g_1(x)=3\cdot 6 = 18$

Finally, the 3rd iteraction is given by:

$g_3(x)=3g_2(x)=3\cdot 18=54$

Here in this problem the function that we have to use is

$g(x)=\frac{1}{3}x+1$

The initial value is

$x=2$

So the first iteration is given by

$g_1(x)=\frac{1}{3}\cdot 2 + 1 = \frac{5}{3}$

To find the 2nd iteration, we substitute this value into g(x) again:

$g_2(x)=\frac{1}{3}g_1+1=\frac{1}{3}\cdot \frac{5}{3}+1=\frac{5}{9}+1=\frac{14}{9}$

Finally, to find the 3rd iteration, we substitute this value into g(x) again:

$g_3(x)=\frac{1}{3}\cdot \frac{14}{9}+1=\frac{14}{27}+1=\frac{41}{27}$

The function in this problem is

$g(x)=-|x-2|+3$

The initial value is

x = 0.5

So, the first iteration is:

$g_1(x)=-1|0.5-2|+3=-1|-1.5|+3=-1\cdot 1.5 +3=-1.5+3=1.5$

The second iteration is given by

$g_2(x)=-|g_1-2|+3=-|1.5-2|+3=--0.5+3=2.5$

Finally, the 3rd iteration is

$g_3(x)=-|g_2-2|+3=-|2.5-2|+3=-0.5+3=2.5$

5 0

3 years ago