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uranmaximum [27]

2 years ago

11

5. The length of a rectangle is 3 units shorter than one-third of the width, x. Which expression represents the perimeter of the

rectangle?
Why is that answer correct?
8/3x−6
2/3x−4
8/3x−2
2/3x−8

1 answer:

ikadub [295]2 years ago

7 0

Answer:

Step-by-step explanation:

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Serena has a summer job as a lifeguard at the neighborhood pool. She earns $240 a week. By rounding her weekly income to the nea

Nesterboy [21]

<h2>Answer: B </h2>

Step-by-step explanation:

If your rounding her weekly income you would go down to $200 then take that times 11 for each week, giving you $2,200 roughly

3 0

3 years ago

Mathhrjirjrrggghuughihihughhhg

marusya05 [52]

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2 years ago

insurance company checks police records on 559 accidents selected at random and notes that teenagers were at the wheel in 91 of

ss7ja [257]

Answer: $(13.22\%,\ 19.34\%)$

Step-by-step explanation:

Given : Sample space : n= 559

Sample proportion : $\hat{p}=\dfrac{91}{559}=0.162790697674\approx0.1628$

$=16.28\%$

Significance level : $\alpha= 1-0.95=0.05$

Critical value : $z_{\alpha/2}=1.96$

Confidence level for population proportion:-

$\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}\\\\=0.1628\pm (1.96)\sqrt{\dfrac{0.1628(1-0.1628)}{559}}\\\\=0.1628\pm0.030604971367\\\\\approx 0.1628\pm0.0306=(0.1322,\ 0.1934)=(13.22\%,\ 19.34\%)$

Hence, 95% confidence interval for the percentage of all auto accidents that involve teenage drivers.= $(13.22\%,\ 19.34\%)$

7 0

3 years ago

Tind the variable of y x=3y

Morgarella [4.7K]

x=3y

Switch sides

3y=X

Divide 3 both sides to get

T= x/3

7 0

2 years ago

How do you find vertical, horizontal and oblique asymptotes for f(x) = (5x-15 )/ (2x 14)?

Andrei [34K]

For vertical asymptotes, find the values which make the function indetermine in this case x=-7,so this is the only vertical asymptote.
For horizontal asymptotes, find the limit when x tends to infinity:
=(5x/x-15/x)/(2x/x+14/x) = 5/2, this is the horizontal asymptote y=5/2
For obliques, you have to meet the degree of the numerator is exactly a greater degree than the denominator, in this case they are the same degree so no oblique asymptote.

6 0

3 years ago