(Y-3)^2 = 4y -12 <=> Y^2 - 6Y + 9 = 4y - 12 <=> 4y = Y^2 - 6Y + 21 <=> y = (Y^2 - 6Y + 21)/4. Solving the equation for y means that we have to express y relative to the other quantities in the equation.

8 0

3 years ago

For each pair of functions F and G below, find f(g(x)) and g(f(x)).

8090 [49]

Answer:

Step-by-step explanation:

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8 0

3 years ago

Suppose the diameter of a circle is 4. What is its radius? and please explain

Olin [163]

The radius of a circle is always half of the diameter of the circle. In this case, the diameter is $4$ , meaning that when we halve $4$ , we will get our radius. Therefore, the radius of the circle is $\boxed{2}$ . Hope this has helped you understand and have a great day!

6 0

3 years ago

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