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mr_godi [17]
3 years ago
9

2.3 x (-1.2) Just multiply -27.6 -2.76 2.76 27.6

Mathematics
1 answer:
____ [38]3 years ago
7 0
It’s -2.76 okkkkkkkkkkkkkkkk byeeereeee
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Brandon purchased a new guitar in 2012. The value of his guitar, t years after he bought it, can be modeled by the function A(t)
Arte-miy333 [17]

Answer: The rate of change in the value of the guitar is modeled by 0.95, which represents a decrease of 5% per year.

Step-by-step explanation:

Hi, to answer this question we have to apply an exponential decay function:  

A = P (1 - r) t  

Where:  

p = original price

r = decrease rate (decimal form)  

t= years  

A = price after t years  

Replacing with the values given:  

A(t)=145(0.95)t.

Where

0.95 = 1-r

0.95-1 = r

-0.05 =-r

0.05 =r

Converting to percentage form:

0.05 x 100 = 5%

Feel free to ask for more if needed or if you did not understand something.  

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Step-by-step explanation:

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3 years ago
Two sides of a rectangle differ by 3.5cm.Find the dimensions of the rectangle if its perimeter is 67cm.
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Step-by-step explanation:

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Best known for its testing program, ACT, Inc., also compiles data on a variety of issues in education. In 2004 the company repor
GarryVolchara [31]

Answer:

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

Step-by-step explanation:

Check for conditions

For this case in order to use the normal distribution for this case or the 68-95-99.7% rule we need to satisfy 3 conditions:

a) Independence : we assume that the random sample of 400 students each student is independent from the other.

b) 10% condition: We assume that the sample size on this case 400 is less than 10% of the real population size.

c) np= 400*0.74= 296>10

n(1-p) = 400*(1-0.74)=104>10

So then we have all the conditions satisfied.

Solution to the problem

For this case we know that the distribution for the population proportion is given by:

p \sim N(p, \sqrt{\frac{p(1-p)}{n}})

So then:

\mu_p = 0.74

\sigma_p =\sqrt{\frac{0.74(1-0.74)}{400}}=0.0219

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

5 0
3 years ago
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