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Natasha_Volkova [10]
3 years ago
13

What is a the volume of a salt crystal measuring 3.22 x 10^-2 cm by 1.5 x 10^-4 cm by 4.30 x 10^-3 cm?

Chemistry
1 answer:
aleksandr82 [10.1K]3 years ago
5 0
Dimension of the salt crystal is:

Length = 3.22 x 10^-2 cm

Breadth = 1.5 x 10^-4 cm

Height = 4.30 x 10^-3 cm

So it is cuboidal in shape.

Volume = L × B × H

V = 3.22 \times  {10}^{ - 2}  \times 1.5 \times  {10}^{ - 4}  \times 4.30 \times  {10}^{ - 3}  \\  \\ V = 3.22 \times 1.5 \times 4.30 \times  {10}^{ (- 2 - 3 - 4)}  \\  \\ V = 20.769\times  {10}^{ - 9} \\  \\ V = 2.0769 \times  {10}^{ - 8} \\  \\ V  \approx 2.1 \times  {10}^{ - 8} \:  {cm}^{3}  \\  \\  \boxed{ \red{ \bold{answer: a}}}
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PLEASE HELP BEFORE 7 A.M. PACIFIC TIME <br> SEE ATTACHED.
anastassius [24]
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5 0
3 years ago
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The vapor pressure of water at 25.0°c is 23.8 torr. determine the mass of glucose (molar mass = 180 g/mol) needed to add to 500.
svp [43]
Q: A
according to this formula, we can get the mole fraction of water (n):
P(solu) = n Pv(water)
when we have Pv(solu) = 22.8 and Pv(water) = 23.8 so by substitution:
22.8 = n * 23.8
n= 0.958
- we need to get the moles of glucose:
moles of water = 500 g(mass weight) / 18 (molar weight)= 27.7 mol
n = moles of water / ( moles of water + moles of glucose)
0.958   = 27.7 / ( 27.7+ moles of glucose)
0.958 moles of glucose + 26.5 = 27.7
0.968 moles of glucose = 1.2
moles of glucose = 1.253 mol
∴ the mass of glucose = no.of glucose moles x molar mass 
                                      = 1.253 x 180 = 225.5 g
Q: B
here we also need to get n (mole fraction of water )by using this formula:
Pv(solu) = n Pv(water)
when we have Pv(solu)=132 & Pv(water)=150 so, by substition:
132= n * 150
n = 0.88
so, mole fraction of solution = 1 - 0.88 = 0.12
and we can get after that the moles of water = (mass weight / molar mass)
- no.moles of water = 85 g / 18 g/mol = 4.7 moles
- total moles in solution = moles of water / moles fraction of water 
                                        = 4.7 / 0.88 = 5.34 moles 
∴ moles of the solution = total moles in solu - moles of water 
                                       = 5.34 - 4.7 = 0.64 moles solute
∴ the molar mass of the solute = mass weight of solute / no.of moles of solute
                                                    = 53.8 / 0.64 = 84 g/mole

Q: C

moles of urea (NH2)2 CO = mass weight / molar mass
                                           = 4.49 g / 60 g /mol
                                           = 0.07 mol
moles of methanol = mass weight / molar mass 
                                 = 39.9  g / 32  g/mol = 1.25 mol
moles fraction of methanol = moles of methanol / (moles of methanol + moles of urea )
moles fraction of methanol = 1.25 / ( 1.25+0.07) = 0.95
by substitution in Pv formula we will be able to get the vapour pressure of the solu :
Pv(solu) = n P°v
Pv(solu) = 0.95 * 89 mm Hg 
∴Pv(solu) = 84.55 mmHg


 
7 0
3 years ago
Helppppppppppppppppppp me
masya89 [10]
The answer is A.
A pure substance is pure, so it cannot be separated in most cases.
8 0
4 years ago
A solution is prepared from 4.5701 g of magnesium chloride and 43.238 g of water. The vapor pressure of water above this solutio
balandron [24]

Answer:

i = 2.483

Explanation:

The vapour pressure lowering formula is:

Pₐ = Xₐ×P⁰ₐ <em>(1)</em>

For electrolytes:

Pₐ = nH₂O / (nH₂O + inMgCl₂)×P⁰ₐ

Where:

Pₐ is vapor pressure of solution (<em>0.3624atm</em>), nH₂O are moles of water, nMgCl₂ are moles of MgCl₂, i is Van't Hoff Factor, Xₐ is mole fraction of solvent and P⁰ₐ is pressure of pure solvent (<em>0.3804atm</em>)

4.5701g of MgCl₂ are:

4.5701g ₓ (1mol / 95.211g) = 0.048000 moles

43.238g of water are:

43.238g ₓ (1mol / 18.015g) = 2.400 moles

Replacing in (1):

0.3624atm = 2,4mol / (2.4mol + i*0.048mol)×0.3804atm

0.3624atm / 0.3804atm = 2,4mol / (2.4mol + i*0.048mol)

2.4mol + i*0.048mol = 2.4mol / 0.9527

2.4mol + i*0.048mol = 2.5192mol

i*0.048mol = 2.5192mol - 2.4mol

i = 0.1192mol / 0.048mol

<em>i = 2.483</em>

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I hope it helps!

4 0
3 years ago
Which mixture can be separated based on differences in the particle size of the components?
Rina8888 [55]

Answer: Mixtures you can separate are like cereal and milk. Hope that helps

Explanation:  Filteration is required to separate a mixture.

So heterogeneous mixures (that contain substances with different particle sizes)  can be separated with a filter.  

Homogeneous mixtures are uniform in composition so they will not be able to be separated.

5 0
4 years ago
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