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makvit [3.9K]
3 years ago
6

Matter can totally be created or destroyed. True False

Chemistry
1 answer:
AnnZ [28]3 years ago
8 0
Yes because E=MC^2 by Einstein
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I need to have a sentence with the word neap tide in it.
olchik [2.2K]
In the absence of neap tide transect data this hypothesis cannot be tested directly, but three pieces of indirect evidence weigh against it as a complete explanation.
3 0
3 years ago
17 p<br> 18 n<br> What is the atomic number of this element?
Verdich [7]

Answer:

Chlorine

Explanation:

The P usually stands for Protons, and that is usually the element number. (chlorine is 17) N is for neutron

6 0
3 years ago
Which answer provides the correct name for name the following hydrocarbon?
natulia [17]
I think the correct answer would be the third option. The correct name for the hydrocarbon described above would be 2-heptyne. It has a chemical formula written as CH3 - CH2 - CH2 - CH2 - C ≡ C - CH3. Counting the number of carbons, we have 7 carbon atoms so we use the prefix hepta-. Since it has a triple bond then it is an alkyne. So, it would be named as heptyne. The triple bond is located on the second carbon atom so we write 2 before the name to indicate the location of the triple bond. The name of the compound would be 2-heptyne.
4 0
3 years ago
Read 2 more answers
What are valence electrons ?
Arada [10]

Answer:In chemistry, a valence electron is an outer shell electron that is associated with an atom, and that can participate in the formation of a chemical bond if the outer shell is not closed; in a single covalent bond, both atoms in the bond contribute one valence electron in order to form a shared pair.

Explanation: hope this helped

8 0
3 years ago
What mass of F2 is needed to produce 180 g of PF3 if the reaction has a 78.1% yield?
nexus9112 [7]

Answer:

91.26 g

Explanation:

Given data:

Mass of PF₃ = 180 g

Mass of F₂ required = ?

Solution:

Chemical equation:

P₄ + 6F₂   → 4PF₃

Moles of PF₃:

Number of moles = mass/ molar mass

Number of moles = 180 g/ 88 g/mol

Number of moles = 2.05 mol

Now we will compare the moles of PF₃ with F₂.

                        PF₃            :           F₂

                          4               :           6

                          2.05         :           6/4×2.05 = 3.075

Mass of  F₂:

Mass of F₂ = moles × molar mass

Mass of F₂ = 3.075 mol × 38 g/mol

Mass of F₂ =  116.85 g

If reaction yield is 78.1%:

116.85 /100 ×78.1 = 91.26 g

6 0
3 years ago
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