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Ksivusya [100]
3 years ago
9

Write 63 as a product of prime factors

Mathematics
2 answers:
krok68 [10]3 years ago
5 0
63=

21*3=         

7*3    

       SO THE ANSWER IS 7*3*3, OR 7*3 TO THE SECOND POWER
Alecsey [184]3 years ago
3 0
3*3*7. In other words, 3²*7.
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Please help with this I am completely stuck on it
vaieri [72.5K]

Answer:

f(x)=\sqrt[3]{x-4} , g(x)=6x^{2}\textrm{ or }f(x)=\sqrt[3]{x},g(x)=6x^{2} -4

Step-by-step explanation:

Given:

The function, H(x)=\sqrt[3]{6x^{2}-4}

Solution 1:

Let f(x)=\sqrt[3]{x}

If f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}, then,

\sqrt[3]{g(x)} =\sqrt[3]{6x^{2}-4}\\g(x)=6x^{2}-4

Solution 2:

Let f(x)=\sqrt[3]{x-4}. Then,

f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}\\\sqrt[3]{g(x)-4}=\sqrt[3]{6x^{2}-4} \\g(x)-4=6x^{2}-4\\g(x)=6x^{2}

Similarly, there can be many solutions.

7 0
3 years ago
((sinB)/1+cosB) + ((1+cosB)/sinB) = 2cscB prove that the equation is an identity
Contact [7]

Step-by-step explanation:

If you need any explanation, we can communicate normally

4 0
2 years ago
I need x+y=5 and y=2x-4solved algebraically
schepotkina [342]

Answer:

x = 3; y = 2

Step-by-step explanation:

x + y = 5

y = 2x - 4

<em>Isolate the y in the first equation</em>

y = 5 - x

y = 2x - 4

<em>Substitute the values</em>

5 - x = 2x - 4

<em>Isolate the Variable</em>

9 = 3x

<em>Simplify</em>

3 = x

<em>Plug that into the first equation</em>

3 + y = 5

<em>Subtract 3 from both sides</em>

y = 2

4 0
3 years ago
Read 2 more answers
Clue 1: A black line is shorter than a white line
Katyanochek1 [597]
The black line is shorter than the gray. Let's simplify the rules. (B=Black, W=White, G=Grey

B is less than W which is less than G


That means G is greater than W. B is less than W, which is less than G. Therefore, the black line is not only shorter than the Gray one, but also the shortest out of the three.

I hope this Helps!
3 0
3 years ago
A group of 54 college students from a certain liberal arts college were randomly sampled and asked about the number of alcoholic
Ket [755]

Answer:

t=\frac{5.25-4.73}{\frac{3.98}{\sqrt{54}}}=0.9601  

P-value  

First we find the degrees of freedom given by:

df = n-1= 54-1=53

Since is a two-sided test the p value would be:  

p_v =2*P(t_{53}>0.9601)=0.3414  

Step-by-step explanation:

Data given and notation  

\bar X=5.25 represent the sample mean

s=3.98 represent the sample standard deviation

n=54 sample size  

\mu_o =4.73 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean differs from 4.73, the system of hypothesis would be:  

Null hypothesis:\mu =4.73  

Alternative hypothesis:\mu \neq 4.73  

Since we know don't the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{5.25-4.73}{\frac{3.98}{\sqrt{54}}}=0.9601  

P-value  

First we find the degrees of freedom given by:

df = n-1= 54-1=53

Since is a two-sided test the p value would be:  

p_v =2*P(t_{53}>0.9601)=0.3414  

7 0
3 years ago
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